a*a;a*a*a;d = (a);fprintf('%4u square equals %4u \r', a, b)fprintf('%4u cube equals %4u \r', a, c)fprintf('The square root of %2u is %6.4f \r', a, d)bC =

a = 10;b = a*a;c = a*a*a;d = sqrt(a); fprintf('%4u square equals %4u \r', a, b);fprintf('%4u cube…

Answered: b = a*a; a*a*a; d = |(a); fprintf('%4u…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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assign(self, assignment:Assignment) -> AssignmentResult: """ This function is to simulate the process of the student receiving an assignment, then working on the assignment, then submitting the assignment and finally receiving grade for the assignment. This function will receive an assignment then a grade should be calculated using the following formula: grade = 1 - (Student's current energy X Assignment difficulty level). The min grade a student may receive is 0% (0) After the grade is calculated the student's energy should be decreased by percentage difficulty. Example if the student has 80% (.8) energy and the assignment is a difficultly level .2 there final energy should be 64% (.64) = .8 - (.8 * .2). The min energy a student may have is 0% (0) Finally the grade calculated should be stored internally with in this class so it can be retrieved later. Then an Assignment Result object should be created with the student's ID, the assignment…
Whats wrong with this code? # This program is to find roots of quadratic equationimport math # function for finding the rootsdef equationroots(a, b, c): # calculating discriminant using formuladis = b * b - 4 * a * csqrt_val = math.sqrt(abs(dis)) # checking condition for discriminantelif dis > 0:print("\nreal and different roots ")print("First solution =",(-b + sqrt_val)/(2 * a))print("second solution =",(-b - sqrt_val/(2 * a)) elif dis == 0:print("\nReal and same roots")print(-b/(2*a)) # when discriminant is less than 0else:print("\nComplex Roots")print("First solution =",-b/(2 * a), "+i", sqrt_val)print("Second solution =",-b/(2 * a), "+i", sqrt_val) # Driver Program a = int(input("Enter a: "))b = int(input("Enter b: "))c = int(input("Enter c: ")) # if a is 0, then incorrect equationif a == 0:print("Input correct quadratic equation") else:equationroots(a, b, c)
QUESTION 10 Determine all the output from the following segment of the program as it would appear on the screen. int my_function1(); void my_function2(int = 15); float my_function3(int &); int main() { %3D int x = 25, у; float z; y = my_function1(); cout <« "y: my_function2(); z = my_function3(x); cout <« "z: " « z « endl; my_function2(x); <« y « endl; <« x « endl; %3D cout <« "x: return 0; } pint my_function1() { int x = 1; x += 15; return x; } avoid my_function2(int y) { static int x = 24;

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b = a*a; a*a*a; d = |(a); fprintf('%4u square equals %4u \r', a, b) fprintf('%4u cube equals %4u \r', a, c) fprintf('The square root of %2u is %6.4f \r', a, d) %3D

b = aa; aa*a; d = |(a); fprintf('%4u square equals %4u \r', a, b) fprintf('%4u cube equals %4u \r', a, c) fprintf('The square root of %2u is %6.4f \r', a, d) %3D