(b) A scientific group claims that the true population mean u is morethan 7 meters.(i) What is the form of the null and alternative hypotheses for testinggroups claim?O(No answer given)Ο 11) Ho :μ = 7, VS ΗA : μ>7||O (2) Ho : µ = 7, VS HA : H < 7O (3)Ho : µ = 7, VS HẠ : µ ± 7 The length of adult male dolphins is normally distributed with anunknown mean H. By some previous knowledge, the populationstandard deviation, is considered as known and is given by o =1m.We took a sample of n = 16 adult male dolphins, finding the samplemean x = 7.3 meters.

Givenclaim is that the true population mean μ is more than 7 metersMean(x)=7.3sample size(n)=16σ=1

Answered: (b) A scientific group claims that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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5.A researcher is interested in the effectiveness of a new program at reducing the average systolicblood pressure in a population with a new anti-hypertensive medication. The researcher wants totest the hypothesis that the mean difference in systolic blood pressure is greater than 40 mmHG.Which of the following represents the correct null and alternative hypotheses for the study?A) Ho: µ1 - µ2 = 0, Ha: µ1 - µ2 = 40B) Ho: µ1 - µ2 = 40 Ha: µ1 - µ2 ≠ 40C) Ho: µD = 40 Ha: µD >40D) Ho: µD = 40 Ha: µD ≠40
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For this study, we should use The null and alternative hypotheses would be: z-test for a population proportion or t-test for a population mean Ho: (p or u) (please enter a decimal) H1: (p or u) (Please enter a decimal) The test statistic z = (please show your answer to 3 decimal places.) The critical value = (Please show your answer to 3 decimal places.) The test statistic (is or is not) in the rejection region. Based on this, we should (reject or accept or fail to accept) the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger 50% at � = 0.05, so there is not sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is larger 50%. The data suggest the populaton proportion is significantly larger 50% at � = 0.05, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is…
QUESTION 9 In the case of over-identification: а. you can use the F-statistic in a test of overidentifying restrictions. you cannot use TSLS for estimation purposes. С. you must rely on your personal knowledge of the empirical problem at hand to assess whether the instruments are exogenous. d. OLS and TSLS yield the same estimate. е. All of the above. f. None of the above.
highschool A and B reported the following summary of MCAT scores. Test claim that the applicants of freshmen in school A score higher than their counterparts of freshmen school B. (a) α = 10%, Classical approach, and conclude it (b) p-value to conclude it school A : n=10, X bar=415, S2 = 100, school B : n=7, X bar=410,S2 = 128 standard eRROR ESTIMATE= 15 P-value: t-distribution, we find the p-value is = to 0.1811 for the one-tailed test. P-value 1811> signi. level a=0.05, fail 2reject. .... not significant evidence to conclude that applicants of School A scored higher than applicants of School B.
(3) The weights of adult black squirrels are known to be normally distributed with mean µ and standard deviation o = 0.12 lbs. A random sample of nine black squirrels gave their average weight to be o.78 lbs. It is hypothesized that due to various reasons the black squirrels are becoming heavier. If the null hypothesis is Ho : H s 0.75 lbs, versus H1 : µ > 0.75 find the p-value The following``answers" have been proposed. (a) By consulting a standard normal table, the p-value is sup P(X9 2 0.78) = P(Z > 1.645) = 0.05. HS0.75 (b) By consulting a standard normal table, the p-value is sup P(X9 2 0.78) = P(Z > 1.00) = 0.1587. HS0.75 (c) By consulting a standard normal table, the p-value is sup P(X9 2 0.78) = P(Z > 0.75) = 0.2266. µ 0.50) = 0.3085. µ<0.75 (e) None of the above The correct answer is (a) (b) (d) N/A (Select One)
16: How do you solve?
Answers: 1. a) χ2 = 4.112, do not reject H0: gender and age of contracting the disease are independent; b) χ2 = 14.03, reject H0: the data do not support the researcher's beliefs; Answer back quickly plz c) χ2 = 2.068, do not reject H0: it appears that this belief is not supported (there is no evidence to suggest that the belief is correct).
A random sample of 90 observations produced a mean of ?⎯⎯⎯=26.3 from a population with a normal distribution and a standard deviation ?=2.08.

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(b) A scientific group claims that the true population mean u is more than 7 meters. (i) What is the form of the null and alternative hypotheses for testing groups claim? O(No answer given) O (1) Họ : µ = 7, VS HA : µ > 7 I| O (2) Ho : µ = 7, VS HA : µ < 7 (3) Ho : µ = 7, VS HA : µ 7