(b) A passive band-pass filter was used to filter out some noises and unwanted stray signals. Illustrate the bandpass filter circuit and solve for all R and C values, when the selected low cut-off frequency is equal to the first and second number of the last 3 digit of your matric no., and the high cut-off frequency is equal to the third number of the last 3 digit of your matric no. in kHz respectively (e.g., if your matric no. is 201060020-5, the last 3 digit of your matric no. is 20-5, then the low cut-off frequency is 20 kHz and the high cut-off frequency is 5 kHz).
(b) A passive band-pass filter was used to filter out some noises and unwanted stray signals. Illustrate the bandpass filter circuit and solve for all R and C values, when the selected low cut-off frequency is equal to the first and second number of the last 3 digit of your matric no., and the high cut-off frequency is equal to the third number of the last 3 digit of your matric no. in kHz respectively (e.g., if your matric no. is 201060020-5, the last 3 digit of your matric no. is 20-5, then the low cut-off frequency is 20 kHz and the high cut-off frequency is 5 kHz).
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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please answer question 1.b quickly… please answer base on my matric number not as same like question.. my matric no is 201061325 so the last 3 digit is 325 so the selected low cut-off frequency is equal to the 32 khz while the high cut-off frequency is 5khz … so use the value that i give... thank you
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