### Problem StatementA grindstone in the shape of a solid disk with a diameter of 0.520 m and a mass of 50.0 kg is rotating at 850 rev/min. You press an axe against the rim with a normal force of 160 N (see below), and the grindstone comes to rest in 7.50 s. Find the coefficient of kinetic friction between the axe and the grindstone. There is negligible friction in the bearings.### Diagram DescriptionThe diagram below illustrates the described scenario:- A grindstone is depicted as a solid disk.- The grindstone has a mass labeled as \( m = 50.0 \, \text{kg} \).- The diameter of the grindstone is \( 0.520 \, \text{m} \).- An external force \( F = 160 \, \text{N} \) is applied to the rim of the grindstone by an axe.- The grindstone is initially rotating at \( \omega = 850 \, \text{rev/min} \).The grindstone comes to rest due to the frictional force between the axe and the grindstone over a time period of 7.50 seconds. The goal is to determine the coefficient of kinetic friction.### Analyzing the Diagram- The solid disk represents the grindstone.- An arrow indicating force \( F \) of 160 N is shown applied perpendicular to the surface of the grindstone where the axe meets the rim.- Rotational motion is indicated by an arrow showing the direction of rotation (\( \omega \)).### Key Variables- \( m \) = 50.0 kg (mass of the grindstone)- \( d \) = 0.520 m (diameter of the grindstone)- \( r \) = 0.260 m (radius of the grindstone, \( r = \frac{d}{2} \))- \( \omega \) = 850 rev/min (initial angular speed)- \( F \) = 160 N (normal force applied by the axe)- \( t \) = 7.50 s (time taken for the grindstone to come to rest)### Required CalculationDetermine the coefficient of kinetic friction (\( \mu_k \)) between the axe and the grindstone.

Given data- Diameter d=0.520 m, mass m=50.0 kg, rotation=850 rev/min Normal force F=160 N, time…

b) A grindstone in the shape of a solid disk with diameter 0.520 m and a mass of 50.0 kg is rotating at 850 rev/min. You press an axe against the rim with a normal force of 160 N (see below), and the grindstone comes to rest in 7.50 s. Find the coefficient of kinetic friction be- tween the axe and the grindstone. There is negligible friction in the bearings.

b) A grindstone in the shape of a solid disk with diameter 0.520 m and a mass of 50.0 kg is rotating at 850 rev/min. You press an axe against the rim with a normal force of 160 N (see below), and the grindstone comes to rest in 7.50 s. Find the coefficient of kinetic friction be- tween the axe and the grindstone. There is negligible friction in the bearings.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

Question

### Problem Statement

A grindstone in the shape of a solid disk with a diameter of 0.520 m and a mass of 50.0 kg is rotating at 850 rev/min. You press an axe against the rim with a normal force of 160 N (see below), and the grindstone comes to rest in 7.50 s. Find the coefficient of kinetic friction between the axe and the grindstone. There is negligible friction in the bearings.

### Diagram Description

The diagram below illustrates the described scenario:

- A grindstone is depicted as a solid disk.
- The grindstone has a mass labeled as \( m = 50.0 \, \text{kg} \).
- The diameter of the grindstone is \( 0.520 \, \text{m} \).
- An external force \( F = 160 \, \text{N} \) is applied to the rim of the grindstone by an axe.
- The grindstone is initially rotating at \( \omega = 850 \, \text{rev/min} \).

The grindstone comes to rest due to the frictional force between the axe and the grindstone over a time period of 7.50 seconds. The goal is to determine the coefficient of kinetic friction.

### Analyzing the Diagram

- The solid disk represents the grindstone.
- An arrow indicating force \( F \) of 160 N is shown applied perpendicular to the surface of the grindstone where the axe meets the rim.
- Rotational motion is indicated by an arrow showing the direction of rotation (\( \omega \)).

### Key Variables

- \( m \) = 50.0 kg (mass of the grindstone)
- \( d \) = 0.520 m (diameter of the grindstone)
- \( r \) = 0.260 m (radius of the grindstone, \( r = \frac{d}{2} \))
- \( \omega \) = 850 rev/min (initial angular speed)
- \( F \) = 160 N (normal force applied by the axe)
- \( t \) = 7.50 s (time taken for the grindstone to come to rest)

### Required Calculation

Determine the coefficient of kinetic friction (\( \mu_k \)) between the axe and the grindstone.

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