b+ a 3 3b+3 3a 3 b+2 2a + 1 2 2b-5 -5a-7 2 1 b+2 2a +2 Thse vectors can't possibly be linearly independent. Tell why. Next obtain a linearly independent subset of these vectors which has the same span as these vectors. In other words, find a basis for the span of these vectors.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The vectors given are:

\[ 
\begin{bmatrix}
1 \\
b + 1 \\
a \\
1
\end{bmatrix}, \quad
\begin{bmatrix}
3 \\
3b + 3 \\
3a \\
3
\end{bmatrix}, \quad
\begin{bmatrix}
1 \\
b + 2 \\
2a + 1 \\
1
\end{bmatrix}, \quad
\begin{bmatrix}
2 \\
2b - 5 \\
-5a - 7 \\
2
\end{bmatrix}, \quad
\begin{bmatrix}
1 \\
b + 2 \\
2a + 2 \\
1
\end{bmatrix}
\]

These vectors can’t possibly be linearly independent. Tell why. Next obtain a linearly independent subset of these vectors which has the same span as these vectors. In other words, find a basis for the span of these vectors.
Transcribed Image Text:The vectors given are: \[ \begin{bmatrix} 1 \\ b + 1 \\ a \\ 1 \end{bmatrix}, \quad \begin{bmatrix} 3 \\ 3b + 3 \\ 3a \\ 3 \end{bmatrix}, \quad \begin{bmatrix} 1 \\ b + 2 \\ 2a + 1 \\ 1 \end{bmatrix}, \quad \begin{bmatrix} 2 \\ 2b - 5 \\ -5a - 7 \\ 2 \end{bmatrix}, \quad \begin{bmatrix} 1 \\ b + 2 \\ 2a + 2 \\ 1 \end{bmatrix} \] These vectors can’t possibly be linearly independent. Tell why. Next obtain a linearly independent subset of these vectors which has the same span as these vectors. In other words, find a basis for the span of these vectors.
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