Analysis of Plane Truss using Method of Sections. Determine the force in members specified per question, and determine also if the force is tension (T) or compression (C). Use only the Method of Sections in your computation. B80 kND1m1m1 m50 kNFAB = 5.56 kN tensionFAE = 75.56 kN tensionFBC= 4.45 kN tensionFBE = 3.34 kN compressionFcD = 88.87 kN compressionFCE = 5.57 kN tension%3DFer = 50 kN tensionFpp = 71.11 kN tensionFFE = 71.11 kN tension0.75 m

Answered: Image /qna-images/answer/09075e37-435a-41d1-9cab-50f36fb08c56.jpg

B 80 kN D 1m 1m 1 m 50 kN FAB = 5.56 kN tension FAE = 75.56 kN tension FBC = 4.45 kN tension FBE = 3.34 kN compression FcD = 88.87 kN compression FCE = 5.57 kN tension %3D Fer = 50 kN tension Fpp = 71.11 kN tension FFE = 71.11 kN tension 0.75 m

B 80 kN D 1m 1m 1 m 50 kN FAB = 5.56 kN tension FAE = 75.56 kN tension FBC = 4.45 kN tension FBE = 3.34 kN compression FcD = 88.87 kN compression FCE = 5.57 kN tension %3D Fer = 50 kN tension Fpp = 71.11 kN tension FFE = 71.11 kN tension 0.75 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Plane and Space Trusses

In civil engineering, a truss is the most important structure that forms the most fundamental member of any building structure and commercial complexes. Trusses are composed of individual members or links that are interconnected by suitable joints, such as rivets, welds, or bolts, and nuts. In trusses, the interconnection leads to the formation of a series of triangles joined together such that all the triangular members behave as a single rigid body. In a simple truss, three members are connected to form a truss member. In trusses, the force always acts at the joints or the interconnection between the individual members.

Question

Analysis of Plane Truss using Method of Sections. Determine the force in members specified per question, and determine also if the force is tension (T) or compression (C). Use only the Method of Sections in your computation.

B
80 kN
D
1m
1m
1 m
50 kN
FAB = 5.56 kN tension
FAE = 75.56 kN tension
FBC
= 4.45 kN tension
FBE = 3.34 kN compression
FcD = 88.87 kN compression
FCE = 5.57 kN tension
%3D
Fer = 50 kN tension
Fpp = 71.11 kN tension
FFE = 71.11 kN tension
0.75 m

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