B 3 35 A =? Ob = 3.28 Ob= 1.28 Ob= 2.28 Ob=4.28

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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### Educational Content on Solving Right Triangles

#### Problem Description:
You are given a right-angled triangle \( \triangle ABC \) with the right angle at \( C \). The length of the side \( BC \) is provided as \( 3 \) units, and the angle \( \angle BAC \) is \( 35^\circ \). The goal is to determine the length of side \( b \), which corresponds to \( AB \).

#### Diagram Explanation:
- **Vertices**: The triangle has three vertices labeled as \( A \), \( B \), and \( C \).
- **Sides**:
  - \( BC \): Height (vertical side) with a length of \( 3 \) units.
  - \( CA \): Base (horizontal side).
  - \( AB \): Hypotenuse, labeled as \( b \).
- **Angles**:
  - \( \angle BCA \): Right angle (\( 90^\circ \)).
  - \( \angle BAC \): \( 35^\circ \).

#### Question:
What is the value of \( b \)?

#### Options:
1. \( b = 3.28 \)
2. \( b = 1.28 \)
3. \( b = 2.28 \)
4. \( b = 4.28 \)

#### Solution Approach:
To find the length of the hypotenuse \( b \) in a right-angled triangle, we use trigonometric ratios. In this case:
\[ \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \]

Given:
- \( \theta = 35^\circ \)
- Adjacent side \( BC = 3 \)

We need to find the hypotenuse \( b \):
\[ \cos(35^\circ) = \frac{3}{b} \]

Rearranging to find \( b \):
\[ b = \frac{3}{\cos(35^\circ)} \]

By calculating \( \cos(35^\circ) \) and solving for \( b \):
\[ b \approx \frac{3}{0.8192} \]
\[ b \approx 3.66 \]

However, our solution shows that none of the provided options are precisely accurate. Double-check the cosine value and recalculate to ensure the closest numerical match to the provided options.

Thus, considering the standard options format and
Transcribed Image Text:### Educational Content on Solving Right Triangles #### Problem Description: You are given a right-angled triangle \( \triangle ABC \) with the right angle at \( C \). The length of the side \( BC \) is provided as \( 3 \) units, and the angle \( \angle BAC \) is \( 35^\circ \). The goal is to determine the length of side \( b \), which corresponds to \( AB \). #### Diagram Explanation: - **Vertices**: The triangle has three vertices labeled as \( A \), \( B \), and \( C \). - **Sides**: - \( BC \): Height (vertical side) with a length of \( 3 \) units. - \( CA \): Base (horizontal side). - \( AB \): Hypotenuse, labeled as \( b \). - **Angles**: - \( \angle BCA \): Right angle (\( 90^\circ \)). - \( \angle BAC \): \( 35^\circ \). #### Question: What is the value of \( b \)? #### Options: 1. \( b = 3.28 \) 2. \( b = 1.28 \) 3. \( b = 2.28 \) 4. \( b = 4.28 \) #### Solution Approach: To find the length of the hypotenuse \( b \) in a right-angled triangle, we use trigonometric ratios. In this case: \[ \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \] Given: - \( \theta = 35^\circ \) - Adjacent side \( BC = 3 \) We need to find the hypotenuse \( b \): \[ \cos(35^\circ) = \frac{3}{b} \] Rearranging to find \( b \): \[ b = \frac{3}{\cos(35^\circ)} \] By calculating \( \cos(35^\circ) \) and solving for \( b \): \[ b \approx \frac{3}{0.8192} \] \[ b \approx 3.66 \] However, our solution shows that none of the provided options are precisely accurate. Double-check the cosine value and recalculate to ensure the closest numerical match to the provided options. Thus, considering the standard options format and
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