B 10 Bx = 12.2 cm Consider vector B pictured below and the given length for Bx=12.2cm and 9 = 24.0° What is the length. (the hypotenuse) of vector B?
B 10 Bx = 12.2 cm Consider vector B pictured below and the given length for Bx=12.2cm and 9 = 24.0° What is the length. (the hypotenuse) of vector B?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Vector Length Calculation**
Consider vector \( B \) pictured below and the given length for \( B_x = 12.2 \, \text{cm} \) and \( \theta = 24.0^\circ \). What is the length (the hypotenuse) of vector \( B \)?
**Diagram Details:**
- The diagram shows a right triangle formed by vector \( B \).
- \( B_x = 12.2 \, \text{cm} \) is the horizontal component along the x-axis.
- \( \theta = 24.0^\circ \) is the angle between \( B_x \) and vector \( B \).
- Vector \( B \) is represented as the hypotenuse of the triangle, extending from the origin.
- A vertical line is drawn from the endpoint of \( B_x \) to the endpoint of vector \( B \), indicating the vertical component.
To find the length of vector \( B \), use the cosine function:
\[
\cos(\theta) = \frac{B_x}{B}
\]
Solve for \( B \):
\[
B = \frac{B_x}{\cos(\theta)}
\]
Calculate using the given values.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffaa99955-7746-4c30-99a1-9c26ca674030%2Fce1a534a-aa31-4909-8e81-6d2b2df63d79%2Fmc7uoxi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Vector Length Calculation**
Consider vector \( B \) pictured below and the given length for \( B_x = 12.2 \, \text{cm} \) and \( \theta = 24.0^\circ \). What is the length (the hypotenuse) of vector \( B \)?
**Diagram Details:**
- The diagram shows a right triangle formed by vector \( B \).
- \( B_x = 12.2 \, \text{cm} \) is the horizontal component along the x-axis.
- \( \theta = 24.0^\circ \) is the angle between \( B_x \) and vector \( B \).
- Vector \( B \) is represented as the hypotenuse of the triangle, extending from the origin.
- A vertical line is drawn from the endpoint of \( B_x \) to the endpoint of vector \( B \), indicating the vertical component.
To find the length of vector \( B \), use the cosine function:
\[
\cos(\theta) = \frac{B_x}{B}
\]
Solve for \( B \):
\[
B = \frac{B_x}{\cos(\theta)}
\]
Calculate using the given values.
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