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b- 0.46 M c- 0.52 M 3) A 3..23 g sample of impure lead nitrate was analyzed by gravimetric analysis to determine the percentage of lead by mass present. Sodium sulphate was delivered from a buretle to precipitate the lead ions as lead sulphate. The precipitate was filtered, washed, and dried before been weighed. When weighed, the precipitate had a mass of 1.44 g. the mass percent of Pb in impure sample is Pb(NO3)2 + Na₂SO4 PbSO4-2NaNO (fw for PbSO4 303.26 g/mol and Atomic mass for 'pb 207.2 g/mol) a-60.59% b-44.27% c-80.71% 5) H (MW 241.86 g/mol) c-1.37 M d-30.46% 4) the pH for the solution that result from mixing of 50 ml 0.020 M in HC1 and 100 ml of 0010 a- 2.87 b-1.18

b- 0.46 M c- 0.52 M 3) A 3..23 g sample of impure lead nitrate was analyzed by gravimetric analysis to determine the percentage of lead by mass present. Sodium sulphate was delivered from a buretle to precipitate the lead ions as lead sulphate. The precipitate was filtered, washed, and dried before been weighed. When weighed, the precipitate had a mass of 1.44 g. the mass percent of Pb in impure sample is Pb(NO3)2 + Na₂SO4 PbSO4-2NaNO (fw for PbSO4 303.26 g/mol and Atomic mass for 'pb 207.2 g/mol) a-60.59% b-44.27% c-80.71% 5) H (MW 241.86 g/mol) c-1.37 M d-30.46% 4) the pH for the solution that result from mixing of 50 ml 0.020 M in HC1 and 100 ml of 0010 a- 2.87 b-1.18

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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