az az an 1. Given Equation 3.2 and Equation 3.2a as shown below, and R = X₁ X₂ X as the form of a product of the respective primary variables raised to exponents. Proof that Equation 3.2 is equal to Equation 3.2a. Hint: using the partial derivative of R with respect to x; where i=1,2,..., n. (²) + (-) +---+ (T ** - Σ(**)*** WR R Xi 1/2 [3.2a] [3.2]
az az an 1. Given Equation 3.2 and Equation 3.2a as shown below, and R = X₁ X₂ X as the form of a product of the respective primary variables raised to exponents. Proof that Equation 3.2 is equal to Equation 3.2a. Hint: using the partial derivative of R with respect to x; where i=1,2,..., n. (²) + (-) +---+ (T ** - Σ(**)*** WR R Xi 1/2 [3.2a] [3.2]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Given Equation 3.2 and Equation 3.2a as shown below, and ? = ?1
?1 ?2
?2 ... ??
??
as the form of a product of the
respective primary variables raised to exponents. Proof that Equation 3.2 is equal to Equation 3.2a. Hint: using
the partial derivative of R with respect to xi where i =1,2,..., n.
![an
1. Given Equation 3.2 and Equation 3.2a as shown below, and R = x₁x₂xn as the form of a product of the
respective primary variables raised to exponents. Proof that Equation 3.2 is equal to Equation 3.2a. Hint: using
the partial derivative of R with respect to x; where i=1,2,..., n.
2
2
27 1/2
ƏR
ƏR
aR
** = [(* )* + ( ² )*+---- ()]
WR=
-W₁
·W₂
+...+
-Wn
axi
Əx₂
WR
xi
* - [E(~_^)]"
=
R
X;
1/2
[3.2a]
[3.2]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5842debd-c7e0-436d-83d9-66a4971dddbf%2F191c3c4b-e8e1-4575-8219-a70a95263cfe%2Fj8aaxcj_processed.png&w=3840&q=75)
Transcribed Image Text:an
1. Given Equation 3.2 and Equation 3.2a as shown below, and R = x₁x₂xn as the form of a product of the
respective primary variables raised to exponents. Proof that Equation 3.2 is equal to Equation 3.2a. Hint: using
the partial derivative of R with respect to x; where i=1,2,..., n.
2
2
27 1/2
ƏR
ƏR
aR
** = [(* )* + ( ² )*+---- ()]
WR=
-W₁
·W₂
+...+
-Wn
axi
Əx₂
WR
xi
* - [E(~_^)]"
=
R
X;
1/2
[3.2a]
[3.2]
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