Aynsleigh runs a business from home and ships items to her customers across the country. She advertises that her company ships 85% of its orders within two working days. She selects an SRS of 50 of the 1000 orders received in the past month to make sure her claim is true. a. What is the mean of the sampling distribution of ?^ ?
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Aynsleigh runs a business from home and ships items to her customers across the country. She advertises that her company ships 85% of its orders within two working days. She selects an SRS of 50 of the 1000 orders received in the past month to make sure her claim is true.
a. What is the mean of the sampling distribution of ?^ ?
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- 105, 82, 94.5, 72.5, 92, 91, 52, 86, 100, 96, 98, 109, 96, 36, 98, 95According to a recent survey, 53% of adults say they never wear a helmet when riding a bike. Suppose we randomly select 180 adults and find 59% of the sample say they never wear a helmet when riding a bike. Which of the following correctly describes the distribution for the proportion of adults in the sample who never wear a helmet when riding a bike? A. pˆ ~ AN(0.59, 0.0367) B. X ~ AN(95.4, 6.6961) C. pˆ ~ AN(0.53, 0.0014) D. pˆ ~ AN(0.53, 0.0372)Let's examine the mean of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 by drawing samples from these values, calculating the mean of each sample, and then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roll an eight-sided die two times (or equivalently, roll two eight-sided dice one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3, 4, 5, 6, 7, and 8. The true mean (µ) of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 is , and the true standard deviation (o) is The number of possible different samples (each of size n = 2) is the number of possibilities on the first roll (8) times the number of possibilities on the second roll (also 8), or 8(8) = 64. If you collected all of these possible samples, the mean of your sampling distribution of means (µM) would equal and the standard deviation of your sampling distribution of means (that is, the standard error or ɑm) would be The following chart…
- #3 Identify the sampling technique used. To ensure customer satisfaction, every 15th phone call received by customer service will be monitored. O A. convenience O B. cluster OC. random O D. systematic O E. stratified Type here to search F5 %23 2. 8 5. E R 4. 6. A 1. SS F. G.Consider a binomial distribution. About 61% of all Salinas residents own a smart phone. Find the mean number of residents own a smart phone when selecting a sample of n = 53 residents.One cable company advertises that it has excellent customer service. In fact, the company advertises that a technician will be there within 30 minutes of when a service call is placed. One frustrated customer believes this is not the truth, claiming that it takes over 30 minutes for the cable repairman to arrive. The customer asks 15 of his neighbors how long it has taken for the cable repairman to arrive when they have called for him. The sample mean for this group is 32.2 minutes with a sample standard deviation of 3.6 minutes. Test the customer’s claim at the 0.02 level of significance. (a) State the null and alternative hypotheses (b) Find the value of your test statistic. Draw a picture and label its location on the normal curve. Also shade the area where you will find the p-value. (c) Calculate the p-value from the sample data. Compare it to the significance level. Label it’s value and location on your bell curve (d) Write a full…
- A pollster wants to know the average income of those who supported John McCain for president. He asks 100 supporters and calculates a mean of $67,543. Is this mean x overbar or mu ? A. mu , because it is calculated based off data from the entire population.. B. x overbar , because it is calculated based off data from the entire population. C. mu , because it is calculated based off data from a sample. D. x overbar , because it is calculated based off data from a sample.Three students want to estimate the mean pencil weight of their schoolmates.To do this, they each randomly chose 5 schoolmates and weighed their pencils. The samples are shown in the table.A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 56 people she sampled who work out in the morning have a mean of 4.4 hours of exercise each week. The 63 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.7 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2: Construct a 99% confidence interval for the true difference between the mean amounts of…
- Let’s examine the mean of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 by drawing samples from these values, calculating the mean of each sample, and then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roll a ten-sided die two times (or equivalently, roll two ten-sided dice one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. The true mean (μ) of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is , and the true standard deviation (σ) is . The number of possible different samples (each of size n = 2) is the number of possibilities on the first roll (10) times the number of possibilities on the second roll (also 10), or 10(10) = 100. If you collected all of these possible samples, the mean of your sampling distribution of means (μMM) would equal , and the standard deviation of your sampling distribution of means (that is, the…The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technician instructed the production foreman to shut down the manufacturing process last week. Technician Shutdowns Taylor Hurley Gupta Rousche Huang 2 a. How many samples, without replacement, of size two are possible? Different samples b. List all possible samples of two observations each and compute the mean of each sample. (Round your answers to 1 decimal place.) Shutdowns Mean c. Compare the mean of the sample means with the population mean. (Round your answers to 1 decimal place.) The mean of the sample means is The population mean is
