From question (xi) to (xx)All...with explanation 4.Let us solve:(i) 3y-20=160–2y²(ii) (2x+1)² +(x+1)² = 6x+47(iii) (x-7) (x-9)=195(iv) 3x - 24 ,x =0 (v)+-15(iv) 3x – 24-X x#0(vi) 10x-X1.= 3, x # 0X +0%3DXX(vii) -+2=0, x # 0(x-2)(viii) (x+2) + 6 (-6) =1, x#-2, 6.1.x+1(x) x+1T(Ix) x-3 x+56> X# 3, -5ax+b _ cx+d(xi) a+bxc+dx la=b, c#d], X #-5, dx+1 212, X0,-1Xa -C5a (xii) (2x+1) +2x+1=4, x + -2x+15 – 35, x+-3%3D%3DxE =+ **-1 (xiv) 3x+1x+13 5(xiii)x+7 =35, x#-1,1,1b x X#0,-(a+b)-7조+3 + 6 (3) =5, x + 3, -3x+(xvi) a+b+x%3Dax+a 2(xvii) () -5G) +6=0,x#a1.1.(xviii) x x+bX#0, -bX-aa a+b(xix)(x–1)(x-2)(х-2)(х-3) (х-3)(х-4) -,x #1, 2, 3, 4b+x-b=x-c• X # a, b, c (xxi) x²-(3 +2)x+2/3 =0a2c(xx):X-a'x-b=X-CApplication: 16. My maternal uncle travelled 84 kms. by cycle and observed that if he wouldbe cycling with the speed of 5kms/hr more, then the time taken to complete the journey isreduced by 5 hrs. let me calculate and write the speed of my maternal uncle's journey in km/hr.

Name: From question (xi) to (xx)All...with explanation 4.Let us solve:(i) 3y
Uploaded: 2024-03-20T06:38:44.000Z
Channel: Bartleby
Description: From question (xi) to (xx)All...with explanation 4.Let us solve:(i) 3y-20=160–2y²(ii) (2x+1)² +(x+1)² = 6x+47(iii) (x-7) (x-9)=195(iv) 3x - 24 ,x =0 (v)+-15(iv) 3x – 24-X x#0(vi) 10x-X1.= 3, x # 0X +0%3DXX(vii) -+2=0, x # 0(x-2)(viii) (x+2) + 6 (-6)