AW14×142 is used as a column having a length of 9m long. It is hinged at the upper end and fixed at the lower end but there is a lateral bracing perpendicular to the minor axis of the W section at a point 5.4m above the bottom support. It is assumed to be pinned connected at the bracing point. Using A36 steel F, = 248MPA and the NSCP Specifications. E, = 200000MPA Properties of the W14X142 A = 26967.69mm² d = 374.65mm by t; = 27.00mm tw = 17.27mm I, = 695.11 × 10ʻmm* I, = 274.71 × 10%mm* S = 3719.86 x 10³mm³ Sy = 1396.18 x 103mm³ r, = 160.53mm ry = 100.84mm = 393.70mm %3D Assume K, = 0.8 for 9.0m length K, = 1.9 for the 3.6m length Ky = 0.80 for the 5.4m length a. Compute the critical slenderness ratio b. Compute the allowable stress F c. Compute the allowable critical load that the column can carry
AW14×142 is used as a column having a length of 9m long. It is hinged at the upper end and fixed at the lower end but there is a lateral bracing perpendicular to the minor axis of the W section at a point 5.4m above the bottom support. It is assumed to be pinned connected at the bracing point. Using A36 steel F, = 248MPA and the NSCP Specifications. E, = 200000MPA Properties of the W14X142 A = 26967.69mm² d = 374.65mm by t; = 27.00mm tw = 17.27mm I, = 695.11 × 10ʻmm* I, = 274.71 × 10%mm* S = 3719.86 x 10³mm³ Sy = 1396.18 x 103mm³ r, = 160.53mm ry = 100.84mm = 393.70mm %3D Assume K, = 0.8 for 9.0m length K, = 1.9 for the 3.6m length Ky = 0.80 for the 5.4m length a. Compute the critical slenderness ratio b. Compute the allowable stress F c. Compute the allowable critical load that the column can carry
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:AW14×142 is used as a column having a length of 9m long. It is hinged at the upper end and fixed at the lower end
but there is a lateral bracing perpendicular to the minor axis of the W section at a point 5.4m above the bottom
support. It is assumed to be pinned connected at the bracing point. Using A36 steel F, = 248MP and the NSCP
Specifications. E, = 200000MP
Properties of the W14X142
A = 26967.69mm²
d = 374.65mm
by
t, = 27.00mm
Sy = 1396.18 × 10³mm³
r, = 160.53mm
ry = 100.84mm
tw = 17.27mm
I, = 695.11 × 10ʻmm*
%3D
= 393.70mm
Iy
= 274.71 x 10ómm*
Sz = 3719.86 × 10³mm³
Assume K, = 0.8 for 9.0m length
K, = 1.9 for the 3.6m length
K, = 0.80 for the 5.4m length
a. Compute the critical slenderness ratio
b. Compute the allowable stress F.
c. Compute the allowable critical load that the column can carry

Transcribed Image Text:hing ed
3.6m
3.6
Laterul suppart
W 14 x 142
vateral support
(assume to be
pinned connected)
5.4m
fixed
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