average velocity of 0.9 m/s shown in Figure 4. The dynamic viscosity of water µ = 1.307 × 10-3 kg/m*s) For laminar flow the pipe friction factorf= 64/Re. Problem IV: Water is flowing steadily in a 0.12-cm-diameter, 17-m-long pipe at an Water Yo D=0.12 cm odi al bW 0.9 m/s me.rs= Figure 4 Question 16: What is the formula for the head loss due to friction in the pipe? a) hf = f(D/L)(v²/2g) b) h = f(L/D)(V /2g) c) hf = f(D/L)(V/2g) d) hf = f(L/D)(V²/2g) e) None of the above
average velocity of 0.9 m/s shown in Figure 4. The dynamic viscosity of water µ = 1.307 × 10-3 kg/m*s) For laminar flow the pipe friction factorf= 64/Re. Problem IV: Water is flowing steadily in a 0.12-cm-diameter, 17-m-long pipe at an Water Yo D=0.12 cm odi al bW 0.9 m/s me.rs= Figure 4 Question 16: What is the formula for the head loss due to friction in the pipe? a) hf = f(D/L)(v²/2g) b) h = f(L/D)(V /2g) c) hf = f(D/L)(V/2g) d) hf = f(L/D)(V²/2g) e) None of the above
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Could I get a written solution for this question please?
![average velocity of 0.9 m/s shown in Figure 4. The dynamic viscosity of water p = 1.307 ×
10-3 kg/m*s) For laminar flow the pipe friction factorf= 64/Re.
Problem IV: Water is flowing steadily in a 0.12-cm-diameter, 17-m-long pipe at an
Water
di al bW
D=0.12 cm
0.9 m/s
me rs=
Figure 4
Question 16:
What is the formula for the head loss due to friction in the pipe?
a) hf = f(D/L)(v²/2g)
b) h, = f(L/D)(V /2g)
c) hf = f(D/L)(V/2g)
d) hf = f(L/D)(V²/2g)
e) None of the above](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d23b2ff-c734-41be-8946-dc1e3f9cde0e%2Ff408c318-ad11-4d83-8643-df48d0fc278e%2Fy4mrfeq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:average velocity of 0.9 m/s shown in Figure 4. The dynamic viscosity of water p = 1.307 ×
10-3 kg/m*s) For laminar flow the pipe friction factorf= 64/Re.
Problem IV: Water is flowing steadily in a 0.12-cm-diameter, 17-m-long pipe at an
Water
di al bW
D=0.12 cm
0.9 m/s
me rs=
Figure 4
Question 16:
What is the formula for the head loss due to friction in the pipe?
a) hf = f(D/L)(v²/2g)
b) h, = f(L/D)(V /2g)
c) hf = f(D/L)(V/2g)
d) hf = f(L/D)(V²/2g)
e) None of the above
![Question 17
(a) Re
PVD
(b) Re
pV
Du
pD
(c) Re
Vụ
(d) Re
µVp
%3D
D
(e) none of the above
Question 18
What is the value of the Reynolds number of the pipe flow?
(а) 523.67
(b) 191.48
(c) 826.32
(d) 2474.31
(е) 4206.55
Question 19:
What is the value of the pipe friction factor f?
(a) f=0.0372
(b) f=0.0113
(c) f=0.0492
(d) f=0.1261
(e) f=0.0775
Question 20:
What is the head loss in the pipe due to friction?
(a) hf = 45.3m
= 32.0m
(b) hf
(c) hf = 16.8m
(d) he = 91.3m
= 27.9m
%3D
%3D
(e) hf](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d23b2ff-c734-41be-8946-dc1e3f9cde0e%2Ff408c318-ad11-4d83-8643-df48d0fc278e%2Fm0f5bnl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 17
(a) Re
PVD
(b) Re
pV
Du
pD
(c) Re
Vụ
(d) Re
µVp
%3D
D
(e) none of the above
Question 18
What is the value of the Reynolds number of the pipe flow?
(а) 523.67
(b) 191.48
(c) 826.32
(d) 2474.31
(е) 4206.55
Question 19:
What is the value of the pipe friction factor f?
(a) f=0.0372
(b) f=0.0113
(c) f=0.0492
(d) f=0.1261
(e) f=0.0775
Question 20:
What is the head loss in the pipe due to friction?
(a) hf = 45.3m
= 32.0m
(b) hf
(c) hf = 16.8m
(d) he = 91.3m
= 27.9m
%3D
%3D
(e) hf
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