= = Av Ephoton = hv KE = hv – c = 2.998 × 108 m/s h=6.626 x10-34 J.s = 6.63 x 10-34 kg m/s Photoelectric effect follow-up: The minimum energy needed to remove one mole of electrons from the surface of cesium (Cs) metal is 187.9 kJ. As discussed in class, this is equivalent to the electron binding energy or work function () for Cs. Calculate the wavelength (in nm) of a photon that could remove an lectron from the surface of cesium with an acquired kinetic energy (KE) of 3.96 × 10 2º J.
= = Av Ephoton = hv KE = hv – c = 2.998 × 108 m/s h=6.626 x10-34 J.s = 6.63 x 10-34 kg m/s Photoelectric effect follow-up: The minimum energy needed to remove one mole of electrons from the surface of cesium (Cs) metal is 187.9 kJ. As discussed in class, this is equivalent to the electron binding energy or work function () for Cs. Calculate the wavelength (in nm) of a photon that could remove an lectron from the surface of cesium with an acquired kinetic energy (KE) of 3.96 × 10 2º J.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![FIVE STAR.
XX
XX
Worksheet 10: deBroglie and Heisenberg
c = Av
Ephoton
= hv
CHEM 130
1. Photoelectric effect follow-up: The minimum energy needed to remove one mole of electrons from the
KE = hv – &
c = 2.998 × 108 m/s
h=6.626 ×10-34 J.s = 6.63 x 10-34 kg•m²/s
energy or work function (0) for Cs. Calculate the wavelength (in nm) of a photon that could remove an
Fall 2021
surface of cesium (Cs) metal is 187.9 kJ. As discussed in class, this is equivalent to the electron binding
lectron from the surface of cesium with an acquired kinetic energy (KE) of 3.96 x 10 20 J.
XX
XXXXX
XXXXXXX
XXXXX](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F589b1d54-b488-420c-a8e8-88e8bfbec5c5%2F411ee826-ccbf-448f-996f-9676f3ffd36b%2F9h94mkp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:FIVE STAR.
XX
XX
Worksheet 10: deBroglie and Heisenberg
c = Av
Ephoton
= hv
CHEM 130
1. Photoelectric effect follow-up: The minimum energy needed to remove one mole of electrons from the
KE = hv – &
c = 2.998 × 108 m/s
h=6.626 ×10-34 J.s = 6.63 x 10-34 kg•m²/s
energy or work function (0) for Cs. Calculate the wavelength (in nm) of a photon that could remove an
Fall 2021
surface of cesium (Cs) metal is 187.9 kJ. As discussed in class, this is equivalent to the electron binding
lectron from the surface of cesium with an acquired kinetic energy (KE) of 3.96 x 10 20 J.
XX
XXXXX
XXXXXXX
XXXXX
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