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Automobile air bags use the decomposition of sodium azide as their source of gas for rapid inflation. The chemical equation hat represents this reaction is shown below: 2NAN3 (s) + 2Na(s) + 3N2(g) What mass of NaN3 is required to provide 40.0 L of N2 at 25.0 "Cand 763 torr? moles of N2(g) produced= 1.64 moles You are correct moles of NaN3(s) required = 1.09 moles You are correct grams of NaN3(s) required= 71.01 grams

Automobile air bags use the decomposition of sodium azide as their source of gas for rapid inflation. The chemical equation hat represents this reaction is shown below: 2NAN3 (s) + 2Na(s) + 3N2(g) What mass of NaN3 is required to provide 40.0 L of N2 at 25.0 "Cand 763 torr? moles of N2(g) produced= 1.64 moles You are correct moles of NaN3(s) required = 1.09 moles You are correct grams of NaN3(s) required= 71.01 grams

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Automobile air bags use the decomposition of sodium azide as their source of gas for rapid inflation. The chemical equation hat represents this reaction is shown below: 2NAN3 (s) + 2Na(s) + 3N,(g) What mass of NaNa is required to provide 40.0 Lof N, at 25.0 "Cand 763 torr? moles of N2(g) produced = 1.64 moles You are correct moles of NaN3 (s)required = 1,09 moles レ You are correct grams of NaN3(s) required= 71.01 grams
Transcribed Image Text:Automobile air bags use the decomposition of sodium azide as their source of gas for rapid inflation. The chemical equation hat represents this reaction is shown below: 2NAN3 (s) + 2Na(s) + 3N,(g) What mass of NaNa is required to provide 40.0 Lof N, at 25.0 "Cand 763 torr? moles of N2(g) produced = 1.64 moles You are correct moles of NaN3 (s)required = 1,09 moles レ You are correct grams of NaN3(s) required= 71.01 grams
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