Austin throws a rock in the air. The height, h, in feet above the ground by h = -16t2 + 123t+ 40. How long is the rock in the air? Claim: The rock will be in the air for 8 seconds at an initial velocity of 123 ft/sec and an initial height of 40 feet. Reasoning: The equation will be equal to 0 since the height is 0 ft when the rock is on the ground. I solved the equation using the quadratic formula by plugging in a, b and c. The radicand was a perfect square that I was able to take the square root of. I got 2 answers but only one is reasonable for time since time can't be negative. ground is given
Austin throws a rock in the air. The height, h, in feet above the ground by h = -16t2 + 123t+ 40. How long is the rock in the air? Claim: The rock will be in the air for 8 seconds at an initial velocity of 123 ft/sec and an initial height of 40 feet. Reasoning: The equation will be equal to 0 since the height is 0 ft when the rock is on the ground. I solved the equation using the quadratic formula by plugging in a, b and c. The radicand was a perfect square that I was able to take the square root of. I got 2 answers but only one is reasonable for time since time can't be negative. ground is given
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Write a CR for the solved problem. A example of one is attached as well.
For the CR you should answer the question of , do you get 2 real solutions, 1 real solution, or 2 complex solutions?
For your reasoning you should explain how you know. Use the example attached to help you answer.
hints: that plus minus sign means there are two answers. If the number under the square root is positive, you have two real solutions. If the number is negative you have two complex solutions. If the number is 0 under the square root you have 1 real number solution.
Transcribed Image Text:Austin throws a rock in the air. The height, h, in feet above the ground Is
by h = -16t² + 123t+ 40. How long is the rock in the air?
Claim: The rock will be in the air for 8 seconds at an initial velocity of 123 ft/sec and an
initial height of 40 feet.
Reasoning: The equation will be equal to 0 since the height is 0 ft when the rock is on the
ground. I solved the equation using the quadratic formula by plugging in a, b and c. The
radicand was a perfect square that I was able to take the square root of. I got 2 answers but
only one is reasonable for time since time can't be negative.
is given
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
