AU (Bn C))° = (c U Bº)n A°

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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is this true or false? use indirect or direct method to prove

 

 

discrete math 

The image displays a mathematical expression involving set operations and complements. The expression is:

\[
(A \cup (B \cap C))^c = (C^c \cup B^c) \cap A^c
\]

This equation demonstrates one of De Morgan's Laws, which relates the complement of unions and intersections of sets. Here's a breakdown of the components:

- \(A, B, C\) are sets.
- \(\cup\) represents the union of sets, meaning all elements that are in either set.
- \(\cap\) represents the intersection of sets, meaning all elements that are in both sets.
- The superscript \(c\) indicates the complement of a set, meaning all elements not in the set.

According to De Morgan's Law, the complement of a union is the intersection of the complements, and vice versa. This equation specifically shows how to distribute the complement over a union and an intersection.
Transcribed Image Text:The image displays a mathematical expression involving set operations and complements. The expression is: \[ (A \cup (B \cap C))^c = (C^c \cup B^c) \cap A^c \] This equation demonstrates one of De Morgan's Laws, which relates the complement of unions and intersections of sets. Here's a breakdown of the components: - \(A, B, C\) are sets. - \(\cup\) represents the union of sets, meaning all elements that are in either set. - \(\cap\) represents the intersection of sets, meaning all elements that are in both sets. - The superscript \(c\) indicates the complement of a set, meaning all elements not in the set. According to De Morgan's Law, the complement of a union is the intersection of the complements, and vice versa. This equation specifically shows how to distribute the complement over a union and an intersection.
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