attenuation coefficient of lead at 662 keV. Just use the two measurements with lead and give your answer to 2 decimal places in units of cm-¹.

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Attenuation
You acquire a spectrum using the MCA for 200 s for the Cs137 source with no absorber. Setting
a region of interest on the photopeak the Net Area is found to be 82075. Then a thin lead
absorber is placed between the source and the detector and another spectrum acquired. This
time the Net Area is 79606. Another thicker absorber is used and the Net Area found to be
39077. If the lead sheets are 0.032 and 0.25 inches thick respectively then determine the
attenuation coefficient of lead at 662 keV. Just use the two measurements with lead and give
your answer to 2 decimal places in units of cm-¹.
Transcribed Image Text:Attenuation You acquire a spectrum using the MCA for 200 s for the Cs137 source with no absorber. Setting a region of interest on the photopeak the Net Area is found to be 82075. Then a thin lead absorber is placed between the source and the detector and another spectrum acquired. This time the Net Area is 79606. Another thicker absorber is used and the Net Area found to be 39077. If the lead sheets are 0.032 and 0.25 inches thick respectively then determine the attenuation coefficient of lead at 662 keV. Just use the two measurements with lead and give your answer to 2 decimal places in units of cm-¹.
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