ation proportion. Determine the null hypothesis, Ho, and the alternative hypothesis, H,.
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- Suppose you reject the null hypothesis H0: μ = 58. It turns out the population mean is actually equal to 55. You have made Group of answer choices Type I and Type II errors a Type II error a Type I error the correct decisionPLEASE HELP WITH THE PROBLEM BELOW Let pm and pf be the respective proportions of male and female white-crowned sparrows that return to their hatching site. We observed that 124 out of 894 males and 70 out of 700 females returned. Does your result agree that there is no difference between the proportions of male and female white-crowned sparrows that return to their hatching site with α = 0.05? Formulate the hypotheses Finish the hypothesis testing and draw your conclusion (use p-value to test the hypotheses)Life on Other Planets Forty-three percent of people believe that there is life on other planets in the universe. A scientist does not agree with this finding. He surveyed 120 randomly selected individuals and found 69 believed that there is life on other planets. At α=0.01, is there sufficient evidence to conclude that the percentage differs from 43% ? Use the P -value method with tables. :H0 ▼(Choose one) :H1 ▼(Choose one) This hypothesis test is a ▼(Choose one) test. (b)Find the critical value(s). Round the answer to two decimal places. If there is more than one critical value, separate them with commas. Critical Value(s): (c)Compute the test value. Round the answer to at least two decimal places. z= (d)Make the decision. (choose one) the null hypothesis (e)Summarize the results. There is ▼(Choose one) that the percentage of people who believe that there is life on other planets differs from 43% .
- For the situation described below, state the null hypothesis, Ho, and the alternative hypothesis, H, to be tested. (Enter != for # as needed.) A statistical test is designed to show that the proportionp of defectives has decreased below 0.6%. Ho: 0.6 H: 0.6Suppose researchers conducted a study to see if the mean body temperature for adultswas different from 98.6 degrees Fahrenheit. For this study, they took a random sampleof 25 healthy adults and found a mean body temperature of 98.2 degrees Fahrenheit forthe sample with a standard deviation of 0.6 degrees. The temperatures of the sampleparticipants were unimodal and symmetric.a. Write the null hypothesis and alternative hypothesis and define your parameter.b. Show that the necessary conditions (Randomization Condition, 10% Condition,Nearly Normal Condition) are satisfied to perform a hypothesis test. Brieflyexplain how each condition is satisfied.c. Perform the hypothesis test and find the P-value. (To show your work: Writedown which calculator you are using and what values you are entering into thecalculator.)d. Is there strong evidence that the mean body temperature is different than 98.6degrees? Briefly explain how you know.6- Hi Wonderful Bartleby Team (Thanks for all the help I do really aprecciate all you guys do) I need help with this exercise from stats. Thanks in advance
- A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set O Carpeted Uncarpeted 9.4 9.1 16 10.8 6.4 10.8 14.8 8.8 11.5 11.6 13.7 9.4 10.7 12.4 13.4 7.8 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. OA Ho P1 H2 B. Ho H1 F2 OC Ho H= H2For the hypothesis system H0: u=c versus Ha: u doesn't equal c Give the absolute value of the calculated test statistics which would correspond to the standard P-value. Consider the population normally distributed. P-value= 0.026For each effect, state whether the null hypothesis was rejected or not. Calculate the effect size for the effect of stress
- Please use the data to find the hypothesis testThe null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. What parameter is being tested? Ho: P= 0.76 H₁: p>0.76 Choose the correct answer below. Left-tailed OTwo-tailed Right-tailed BLECHPhysical properties of six flame-retardant fabric samples were investigated in an article. Use the accompanying data and a 0.05 significance level to determine whether a linear relationship exists between stiffness x (mg-cm) and thickness y (mm). O Ho: P = 0 H₂: P = 0 O Ho: P = 0 H₂:p>0 State the appropriate null and alternative hypotheses. O Ho: P = 0 Ha: P < 0 O Ho: P = 0 Ha: P = 0 X y r = 7.95 24.63 12.39 7.06 24.17 35.70 0.25 0.64 0.32 0.27 0.80 0.56 Compute the value of the sample correlation coefficient, r. Round your answer to four decimal places. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = P-value = State the conclusion in the problem context. O Fail to reject Ho. The data does not indicate that the population correlation coefficient differs from 0. O Reject Ho. The data indicates that the population correlation coefficient differs from 0. O Reject Ho. The data does not…