ate the coefficient of skewness of the following frequency Distributions, given their corresponding means, medians, and standard deviations as follows and interpret the results: 2.1 Frequency Distribution A Mean (x) = 50.70; Median (Md) = 49.10; and Standard Deviation (s)= 9.20 2.2 Frequency Distribution B Mean (x) = 75.30; Median (Md) = 76.70; and Standard Deviation (s) = 6.80 A group of 10 drivers reported the number of hours they devoted in driving their jeepneys for a particular 10-day period as follows: 6, 8, 10, 12, 7, 5, 14, 10, 9, and 11. Calculate the coefficient of variation for these working hours. the improvement The donations given by 102 persons for the improvement of their church are presented in Table 1 below. Calculate and interpret the results obtained for the following: 4.1 Coefficient of Variation - higher SD than the mean 4.2 Skewness - data are highly skewed 4.3 Kurtosis distribution is too peaked Table 1. Donations of 102 Persons Donation (P) P 100-P 199 P 200-P 299 P 300-P 399 P 400-P 499 P 500-P 599 P 600-P 699 P 700-P 799 P 800-P 899 P 900-P 999 300 -200 160 DO 12⁰ = 10% No. of Persons 5 10 13 18 21 15 9 7 4 Soln For #2 Coefficient of Skewness 2-1 7:50.70 Md = 49.10 0 = 9.10 3(x - Ind) = 3 (50.70 - 40 = 3 (1-6) = 4.8 9.10 SK₁ -> S
ate the coefficient of skewness of the following frequency Distributions, given their corresponding means, medians, and standard deviations as follows and interpret the results: 2.1 Frequency Distribution A Mean (x) = 50.70; Median (Md) = 49.10; and Standard Deviation (s)= 9.20 2.2 Frequency Distribution B Mean (x) = 75.30; Median (Md) = 76.70; and Standard Deviation (s) = 6.80 A group of 10 drivers reported the number of hours they devoted in driving their jeepneys for a particular 10-day period as follows: 6, 8, 10, 12, 7, 5, 14, 10, 9, and 11. Calculate the coefficient of variation for these working hours. the improvement The donations given by 102 persons for the improvement of their church are presented in Table 1 below. Calculate and interpret the results obtained for the following: 4.1 Coefficient of Variation - higher SD than the mean 4.2 Skewness - data are highly skewed 4.3 Kurtosis distribution is too peaked Table 1. Donations of 102 Persons Donation (P) P 100-P 199 P 200-P 299 P 300-P 399 P 400-P 499 P 500-P 599 P 600-P 699 P 700-P 799 P 800-P 899 P 900-P 999 300 -200 160 DO 12⁰ = 10% No. of Persons 5 10 13 18 21 15 9 7 4 Soln For #2 Coefficient of Skewness 2-1 7:50.70 Md = 49.10 0 = 9.10 3(x - Ind) = 3 (50.70 - 40 = 3 (1-6) = 4.8 9.10 SK₁ -> S
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Calculate the coefficient of skewness of the following frequency Distributions, given their
corresponding means, medians, and standard deviations as follows and interpret the results:
-0.52 2.1 Frequency Distribution A
2.2
K2=0.62
Mean (x) = 50.70; Median (Md) = 49.10; and Standard Deviation (s)= 9.20
28.703
3. A group of 10 drivers reported the number of hours they devoted in driving their jeepneys for a
particular 10-day period as follows: 6, 8, 10, 12, 7, 5, 14, 10, 9, and 11. Calculate the coefficient of
variation for these working hours.
Frequency Distribution B
Mean (x) = 75.30; Median (Md) = 76.70; and Standard Deviation (s)= 6.80
#1
amp B
amp A
alıx
4. The donations given by 102 persons for the improvement of their church are presented in Table 1
below. Calculate and interpret the results obtained for the following:
Coefficient of Variation - higher SD than the mean
Skewness - data are highly skewed
distribution is too peaked
34.92 4.1
4.2
0.89
4.3 Kurtosis
168.76
Table 1. Donations of 102 Persons
-
Donation (P
P 100-P 199
P 200 -
299
P300 -
399
P 400 -
499
P500 -
599
P600 - 699
P700-P 799
P 800-P 899
P 900 - 999
зоо
- 200
160
x 100
x 100 %⁰ = 10%
No. of Persons
5
10
13
18
21
15
9
7
4
the improvement of church
Soln For #2
Coefficient of Skewness
2-1 X=50.70
Md = 49.10
0 = 9:10
Sk₁ = 3 (x - md)
= 3(50.70-49.10)
= 3 (1-6)
= 4.8
9.20
-> Skn = 0.52
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