At 288 oC the equilibrium constant for the reaction: 2 HI(g)(equilibrium arrows)  H2(g) + I2(g) is KP = 2.51e-10. If the initial pressure of HI is 0.00240 atm, what are the equilibrium partial pressures of HI, H2, and I2?

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At 288 oC the equilibrium constant for the reaction:

2 HI(g)(equilibrium arrows)  H2(g) + I2(g)

is KP = 2.51e-10. If the initial pressure of HI is 0.00240 atm, what are the equilibrium partial pressures of HI, H2, and I2?



p(HI) =  .


p(H2) =  .


p(I2) =  .


Expert Solution
Step 1

Given: 

K= 2.51 × 10-10 

Initial pressure of HI = 0.00240 atm 

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