At what distance must Pete (mass = 42 kg) stand from his car (mass= 1250 kg) in order to have a force of attraction of 8.3 x 10 7N between them? Round your answer to the nearest whole number. Label in meters.
At what distance must Pete (mass = 42 kg) stand from his car (mass= 1250 kg) in order to have a force of attraction of 8.3 x 10 7N between them? Round your answer to the nearest whole number. Label in meters.
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![At what distance must Pete (mass = 42 kg) stand from his car
(mass = 1250 kg) in order to have a force of attraction of 8.3 x 10
7N between them?
Round your answer to the nearest whole number. Label in meters.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F261a626c-17a7-46a9-8a93-eb8b52d7b03f%2Fd53b099c-d3be-4331-82c9-0524ac0b9111%2Frn0jlq6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:At what distance must Pete (mass = 42 kg) stand from his car
(mass = 1250 kg) in order to have a force of attraction of 8.3 x 10
7N between them?
Round your answer to the nearest whole number. Label in meters.
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