At Western University, the historical mean of scholarship examination scores for freshman applications is 900. A historical population standard deviation $\sigma = 180$ is assumed known. Each year, the assistant dean uses a sample of applications to determine whether the mean examination score for the new freshman applications has changed.**a. State the hypotheses.**- $H_0: \mu =$ [Select your answer]- $H_a: \mu =$ [Select your answer]**b. What is the 95% confidence interval estimate of the population mean examination score if a sample of 200 applications provided a sample mean of $\bar{x} = 935$ (to the nearest whole number)?**[Blank] , [Blank]**c. Use the confidence interval to conduct a hypothesis test. Using $\alpha = 0.05$, can the assistant dean conclude that the mean examination score for the new freshman applications has changed?**- [Select your answer]**d. What is the $p$-value (to 4 decimals)? (Use Table 1 from Appendix B.)**[Blank]

The given data is as follows:Population mean, Population standard deviation, Sample size, Sample…

Answered: At Western University the historical…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Do people walk faster in the airport when they are departing or when they are arriving? Researchers measured the walking speed of 45 departing travelers and 71 arriving travelers at Sacramento International Airport. They found that departing travelers had a mean walking speed of 256 ft/min, and arriving travelers had a mean walking speed of 241 ft/min. The standard deviation was 31 ft/min for departing travelers and 58 ft/min for arriving travelers. a. Construct a 89% confidence interval for the difference in mean walking speed between departing and arriving travelers. Round your answers to 3 decimals. Use the smallest of the two degrees of freedom. Critical value: 2* or t* Margin of Error: E = Confidence Interval: [ (Enter the positive one.) ]
In a city with three high schools, all the ninth graders took a Standardized Test, with these results: Highschool Mean score of test number of 9th grades Glenwood 81 275 Central City 95 338 Lincoln High 66 172 The city's PR manager, who never took statistics, claimed the mean score of all ninth graders in the city was 83 . Of course, that is incorrect. What is the mean score for all ninth graders in the city? Round to one decimal place. mean of all ninth grader's scores =
Use the table to get the answer b. For the variable EDUC i. What is the mean? ii. What is the standard error of the mean? You will need to calculate this using the appropriate formula – remember, the GSS is a sample of individuals. iii. What is the 99% confidence interval estimate? iv. What is the 95% confidence interval? v. What is the 68% confidence interval? Statistics EDUC Highest year of school completed N Valid 2345 Missing 3 Mean 13.73 Std. Error of Mean .061 Median 14.00 Mode 12 Std. Deviation 2.974 Range 20 Minimum 0 Maximum 20 Sum 32201
4. To estimate the mean retail price of designer jeans, a buyer sampled 19 retailers in New York City and recorded the selling price of the jeans. The following statistics were reported: = 51.75 dollars, and s = 5.50 dollars. Find a 99% confidence interval for the mean.
Which type of confidence interval should you use in this situation? An economics professor randomly selected 100 millionaires in the United States. The average age of these millionaires was 54.8 years with a standard deviation of 7.9 years. What is the 95% confidence interval for the mean age of all United States millionaires? Question 5 options: 1) a confidence interval for the mean using a table value from the standard normal distribution. 2) a confidence interval for the mean using a table value from the t distribution. 3) a confidence interval for a proportion using a table value from the standard normal distribution. 4) a confidence interval for proportion using a table value from the t distribution. 5) none of the above.
Which has the greatest standard error? mean=20, s.d.=10, n=9 mean=30, s.d.=15, n=16 mean=40, s.d.=20, n=25 mean=50, s.d.=25, n=36
Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper car loader is set to put 67 tons of coal into each car. The actual weights of coal loaded into each car are normally distributed, with mean ? = 67 tons and standard deviation ? = 1.7 ton.
Directions: 1. Answer the following items. 2. Find the appropriate sample size given the confidence level, standard deviation, and margin of error. 3. Round off to the nearest whole number. 4. Just write the number, no other symbols or variables, no spacing or comma. Problem: E = 0.88, standard deviation = 15, 95% confidence level
mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 40 home theater systems has a mean price of $138.00. Assume the population standard deviation is $17.80. Construct a 90% confidence interval for the population mean.
Given this data: {4, 5, 8, 11, 16, 8},(a) Find the 90% confidence interval for the mean.(b) Interpret what does the interval mean?
The mall has a set of data with employee age (X) and the corresponding number of annual on-the-job-accidents(Y). Analysis on the set finds that the regression equation is Y=100-3X. What is the likely number of accidents for someone aged 30? 97 100 10 none of the above
Cris Turlock owns and manages a small business in San Francisco, California. The business provides breakfast and brunch food, via carts parked along sidewalks, to people in the business district of the city. Being an experienced businessperson, Cris provides incentives for the salespeople operating the food carts. This year, she plans to offer monetary bonuses to her salespeople based on their individual mean daily sales. Her first task is to see if there is a significant difference in the mean daily sales among the different salespeople. She chooses a "sample" of days for each salesperson and records the sales for each day. She then runs a one-way, independent-samples ANOVA test to determine whether or not she can conclude that at least one salesperson's performances is significantly different from the others. (Otherwise, she'll split the bonuses evenly among all the salespeople.) In her ANOVA, the "groups" are the different salespeople, and the variable of interest is the daily sales…

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