At time to = 0, particle A is released from rest at a height h = 10 m and falls down %3D vertically under the effect of the regular force of gravity as shown in the figure. At the same time t, = 0, particle B is launched from the ground level with a speed v, = 21 m/s at a distance x, = 15 m from where the vertical trajectory of particle A crosses the horizontal, as shown in the figure. Ignore air resistance. ho 0. В (a) Determine the angle 0 at which particle B must be launched for it to collide with particle A. The location of the collision is illustrated in the figure by the crossing of the dashed lines.
At time to = 0, particle A is released from rest at a height h = 10 m and falls down %3D vertically under the effect of the regular force of gravity as shown in the figure. At the same time t, = 0, particle B is launched from the ground level with a speed v, = 21 m/s at a distance x, = 15 m from where the vertical trajectory of particle A crosses the horizontal, as shown in the figure. Ignore air resistance. ho 0. В (a) Determine the angle 0 at which particle B must be launched for it to collide with particle A. The location of the collision is illustrated in the figure by the crossing of the dashed lines.
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Transcribed Image Text:At time to = 0, particle A is released from rest at a height h = 10 m and falls down
%3D
vertically under the effect of the regular force of gravity as shown in the figure. At the same
time t, = 0, particle B is launched from the ground level with a speed v, = 21 m/s at a
distance x, = 15 m from where the vertical trajectory of particle A crosses the horizontal,
as shown in the figure. Ignore air resistance.
ho
0.
В
(a) Determine the angle 0 at which particle B must be launched for it to collide with
particle A. The location of the collision is illustrated in the figure by the crossing of
the dashed lines.
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