At time t=0, the position vector of a particle moving in the x-y plane is r = 4.48i m. By time t = 0.030 s, its position vector has become(4.711 +0.47)) m. Determine the magnitude vay of its average velocity during this interval and the angle 9 made by the average velocitywith the positive x-axis.Answers:im/s4

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At time t=0, the position vector of a particle moving in the x-y plane is r = 4.48i m. By time t = 0.030 s, its position vector has become (4.71i+0.47)) m. Determine the magnitude vay of its average velocity during this interval and the angle 0 made by the average velocity with the positive x-axis. Answers: 0- i i m/s

At time t=0, the position vector of a particle moving in the x-y plane is r = 4.48i m. By time t = 0.030 s, its position vector has become (4.71i+0.47)) m. Determine the magnitude vay of its average velocity during this interval and the angle 0 made by the average velocity with the positive x-axis. Answers: 0- i i m/s

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

Question

At time t=0, the position vector of a particle moving in the x-y plane is r = 4.48i m. By time t = 0.030 s, its position vector has become
(4.711 +0.47)) m. Determine the magnitude vay of its average velocity during this interval and the angle 9 made by the average velocity
with the positive x-axis.
Answers:
i
m/s
4

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