At time t- 0, an electron with kinetic energy 12 keV moves through x 0 in the positive direction of an x axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 77.9 uT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x axis in centimeters when the electron reaches coordinatex= 27 cm? (a) Numberi Units (b) Number Units

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At time t- 0, an electron with kinetic energy 12 keV moves through x = 0 in the positive direction of an x axis that is parallel to the
horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 77.9 uT. (a) What is the
magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance
from the x axis in centimeters when the electron reaches coordinatex = 27 cm?
(a) Number
Units
(b) Number
Units
Transcribed Image Text:At time t- 0, an electron with kinetic energy 12 keV moves through x = 0 in the positive direction of an x axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 77.9 uT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x axis in centimeters when the electron reaches coordinatex = 27 cm? (a) Number Units (b) Number Units
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