At their closest approach, Venus and Earth are 4.20 x 1010m apart. The mass of Venus is 4.87 x 10× 10 24point?24kg, the mass of Earth is 5.97kg, and G = 6.67 x 10 -11 N. m 2/kg 2. What is the magnitude of the gravitational force exerted by Venus on Earth at that6.30 x 1020 N4.62 x 1028 N1.10 x 1018 N1.72 x 1019 N5.43 x 1026 N

Given, Mass of Venus, MV=4.87×1024 kg, Mass of Earth, ME=5.97×1024 kg, distance, d=4.20×1010 m, and…

At their closest approach, Venus and Earth are 4.20 x 10 m apart. The mass of Venus is 4.87 x 10 24 kg, the mass of Earth is 5.97 x 10 24 kg, and G = 6.67 x 10 -11 N· m 2/kg 2. What is the magnitude of the gravitational force exerted by Venus on Earth at that point? O 6.30 x 1020N O 4.62 x 1028 N O 1.10 x 1018 O 1.72 x 1019 N O 5.43 x 1026N

At their closest approach, Venus and Earth are 4.20 x 10 m apart. The mass of Venus is 4.87 x 10 24 kg, the mass of Earth is 5.97 x 10 24 kg, and G = 6.67 x 10 -11 N· m 2/kg 2. What is the magnitude of the gravitational force exerted by Venus on Earth at that point? O 6.30 x 1020N O 4.62 x 1028 N O 1.10 x 1018 O 1.72 x 1019 N O 5.43 x 1026N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The gravitational acceleration (gravitational field) at the surface of a Planet A is 9 m/s². The radius and the mass of Planet B are both three times larger than those of Planet A. What is the gravitational acceleration on Planet B? O 81 m/s? O3 m/s² O 1 m/s2 O 27 m/s? O 9 m/s2
29. Consider Planet X whose mass and radius are 9.05 x 1025 [kg] and 5.95 x 104 [m], respectively. If the weight of the object on the surface of the Earth is 2940 [N], what is its weight at height 750 [m] from the surface of the Planet X? Note: The gravitational constant is G = : 6.6743 x 10-11 m3 A. 3.70 × 108 [N] C. 4.99 x 108 [N] B. 4.88 x 108 [N] D. 5.12 x 108 [N] Lkg
a.) Find the net force on the Moon (mM=7.35×1022kg)(mM=7.35×1022kg) due to the gravitational attraction of both the Earth (mE=5.98×1024kg)(mE=5.98×1024kg) and the Sun (mS=1.99×1030kg)(mS=1.99×1030kg), assuming they are at right angles to each other (Figure 1). Express your answer to three significant figures and include the appropriate units. Fnet= __________ ____________ b.) Determine the direction of the net force. Express your answer to three significant figures and include the appropriate units. θ= ______________ ___________
The Lunar reconnaissance orbiter (LRO) is currently in orbit around the moon on an exploration mission to map its surface. If it has a mass of 1820 kg and is orbiting at an elevation of 65.0 km from the surface, what is the gravitational force acting on the LRO due to the moon? The moon has a mass of 7.348 x 1022 kg and a radius of 1738 km. {G = 6.674 x 10-11 N m2/kg?} r = 1,803 km 1738 km I m, Norbiter = 1,820 kg mmoon 7.348 × 102² kg 65.0 km
Everyone knows the earth is pulled toward the Sun by the gravitational force between the Sun (M = 2 x 10^30kg) and the earth (m = 6 x 10^24kg). What is the gravitational acceleration of the Sun due to the earth's pull (1.5 x 10^11 km apart)?
Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.4 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)What is the force of attraction between Mars and the satellite? 2.)What speed should the satellite have to be in a perfectly circular orbit? 3.)How much time does it take the satellite to complete one revolution?
A sphere of copper has a radius of 50.0 cm and a mass of 4690 kg. A sphere of unknown metal has a radius of 30.0 cm. The surfaces of the spheres are 20.0 cm apart. The force of gravitational attraction between the two spheres is 0.372 mN. What is the mass of the unknown metal?
Find the magnitude of the gravitational force (in N) between a planet with mass 7.25 ✕ 1024 kg and its moon, with mass 2.50 ✕ 1022 kg, if the average distance between their centers is 2.90 ✕ 108 m. N (b) What is the moon's acceleration (in m/s2) toward the planet? (Enter the magnitude.) m/s2 (c) What is the planet's acceleration (in m/s2) toward the moon? (Enter the magnitude.) m/s2
Every few months, memes circulate claiming that certain alignments of the planets with the Earth will result in a change in the gravitational force you feel. Usually these memes state that the alignment will counteract Earth's gravity slightly so you will feel less of a gravitational pull towards the Earth. Can this ever happen? Let's look at the numbers. What is the gravitational force (in N) of the Earth on you (MĚ = 5.97 × 1024 kg, R₁ = 6380 km)? Say your mass is 64 kg. (Enter the magnitude.) What is the gravitational force (in N) of Jupiter on you when it is closest to Earth (M₁ = 1.90 × 1027 kg, R₁ = 5.88 × 108 km)? (Enter the magnitude.) By what factor would the mass of Jupiter need to increase to be equal to the gravitational force you feel from the Earth? Part 1 of 5 The gravitational force between two masses is given by -GMm r² where G = 6.67 x 10-11 m³/s²/kg. FgE Part 2 of 5 We can use this expression to determine the magnitude of the gravitational force you feel while on the…
The radius of Earth is 6.4 x 106 m. Its orbital radius around the Sun is 1.5 x 10¹¹ m. The masses of Earth and the Sun, respectively, are 6 x 1024 kg and 2 x 1030 kg. What is the magnitude of the gravitational force of attraction between Earth and the Sun? 3.6x102² N 5.3x10³³ N 2.0x10³¹ N 31 01. 2x10³8 N
The International Space Station (ISS) completes one orbit of Earth in 92 minutes. What is the radius of the orbit in kilometers (km)? You may assume the orbit is circular. The mass of the ISS is 420 kg, and the mass of the Earth is 6.0×10246.0×1024kg. Newton’s gravitational constant is 6.7×10−11N⋅m2kg26.7×10−11kg2N⋅m2.
You encounter a strange cosmic string in outer space. The string extends along the x axis from x = 0 m to x = 4.6 x 104 m. You are located at x = -5.4 x 104 m. You experience a gravitational field equal to 9.6 x 10-6 N/kg at this location. Assuming the string has a constant linear mass density, calculate this linear mass density, in units of 105kg/m. Use G = 6.7 x 10-11 N m2/ kg2. (Please answer to the fourth decimal place - i.e 14.3225)