At the start of 2010, an online social group had 360 million members. Subsequently, new members joined at a rate of roughly m(t)=-9.9t^2+12t+260 million members per year (0
At the start of 2010, an online social group had 360 million members. Subsequently, new members joined at a rate of roughly m(t)=-9.9t^2+12t+260 million members per year (0
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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At the start of 2010, an online social group had 360 million members. Subsequently, new members joined at a rate of roughly
m(t)=-9.9t^2+12t+260 million members per year (0
![### Problem Statement on Online Social Group Membership Growth
At the start of 2010, an online social group had 360 million members. Subsequently, new members joined at a rate of roughly
\[ m(t) = -9.9t^2 + 12t + 260 \]
million members per year, where \( t \) is time in years since the start of 2010 ( \( 0 \leq t \leq 5 \) ).
#### Tasks:
(a) **Find an expression for the total online social group membership \[ M(t) \] at time \( t \).**
\[ M(t) = \]
(b) **Use the answer to part (a) to estimate the online social group membership midway through 2013.**
(Round your answer to the nearest 1 million members.)
\[ M(3.5) = \] million members](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F61d8df79-6fd2-494a-bfde-d732d93e5033%2F50e08985-71f1-4fd4-8f2e-b4b38478b65c%2Fbgrfks17_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Statement on Online Social Group Membership Growth
At the start of 2010, an online social group had 360 million members. Subsequently, new members joined at a rate of roughly
\[ m(t) = -9.9t^2 + 12t + 260 \]
million members per year, where \( t \) is time in years since the start of 2010 ( \( 0 \leq t \leq 5 \) ).
#### Tasks:
(a) **Find an expression for the total online social group membership \[ M(t) \] at time \( t \).**
\[ M(t) = \]
(b) **Use the answer to part (a) to estimate the online social group membership midway through 2013.**
(Round your answer to the nearest 1 million members.)
\[ M(3.5) = \] million members
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