Chapter 11, Problem 030Z Your answer is partially correct. Try again.At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity isV = - (3.97 m/s) i + (2.00 m/s) j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b)and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j and k components respectively),the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and theforce acting on the object.ememlem(a) NumberUnitsIm/s^2alem(b) NumberUnitsTm/s^2blemablem(c) NumberUnitsm/s^2oblem(d) NumberUnits|kg-m^2/scoblem(e) NumberUnitšTkg-m^2/sroblemUnitTkg-m^2/s(f) Number

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Description: Chapter 11, Problem 030Z Your answer is partially correct. Try again.At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity isV = - (3.97 m/s) i + (2.00 m/s) j + (1.05 m/s

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At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is %3D V = - (3.97 m/s) i + (2.00 m/s) j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b) and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the force acting on the object. and components respectively),

At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is %3D V = - (3.97 m/s) i + (2.00 m/s) j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b) and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the force acting on the object. and components respectively),

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter6: Motion In Two Dimensions

Section6.3: Relative Velocity

Problem 27PP

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

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Question

Chapter 11, Problem 030
Z Your answer is partially correct. Try again.
At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is
V = - (3.97 m/s) i + (2.00 m/s) j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b)
and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j and k components respectively),
the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the
force acting on the object.
em
em
lem
(a) Number
Units
Im/s^2
alem
(b) Number
UnitsTm/s^2
blem
ablem
(c) Number
Units
m/s^2
oblem
(d) Number
Units
|kg-m^2/s
coblem
(e) Number
UnitšTkg-m^2/s
roblem
Unit
Tkg-m^2/s
(f) Number

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