At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is %3D V = - (3.97 m/s) i + (2.00 m/s) j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b) and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the force acting on the object. and components respectively),

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter4: Two-and-three Dimensional Motion
Section: Chapter Questions
Problem 17PQ: A If the vector components of a particles position moving in the xy plane as a function of time are...
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Chapter 11, Problem 030
Z Your answer is partially correct. Try again.
At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is
V = - (3.97 m/s) i + (2.00 m/s) j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b)
and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j and k components respectively),
the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the
force acting on the object.
em
em
lem
(a) Number
Units
Im/s^2
alem
(b) Number
UnitsTm/s^2
blem
ablem
(c) Number
Units
m/s^2
oblem
(d) Number
Units
|kg-m^2/s
coblem
(e) Number
UnitšTkg-m^2/s
roblem
Unit
Tkg-m^2/s
(f) Number
Transcribed Image Text:Chapter 11, Problem 030 Z Your answer is partially correct. Try again. At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is V = - (3.97 m/s) i + (2.00 m/s) j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b) and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j and k components respectively), the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the force acting on the object. em em lem (a) Number Units Im/s^2 alem (b) Number UnitsTm/s^2 blem ablem (c) Number Units m/s^2 oblem (d) Number Units |kg-m^2/s coblem (e) Number UnitšTkg-m^2/s roblem Unit Tkg-m^2/s (f) Number
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