At the horse races (with ten horses competing), in how many ways can the top three places be selected? (Note that no horse may have more than one of the top three places!)

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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## Permutations
The fundamental counting principle is applied when the number of options goes down at each station. We will not use or test the formulas here, although it is in the book.

### Example and Exercise:
**Scenario:** In a club of 12 people, in how many ways can a president, vice-president, and treasurer be selected if no person may have more than one office?

The number of ways can be calculated as:
\[ 12 \times 11 \times 10 = 1,320 \text{ ways} \]

**Problem:** At the horse races (with ten horses competing), in how many ways can the top three places be selected? (Note that no horse may have more than one of the top three places!)

The number of ways can be calculated by:
\[ P \times VP \times T \]

The permutations formula applied for the top three places in the race can be solved as:
\[ 10 \times 9 \times 8 \]

So, the number of ways the top three places can be selected is:
\[ = \_\_\_\_\_ \times \_\_\_\_\_ \times \_\_\_\_\_ = \]

### Diagram Explanation:
This exercise includes a blanks graph at the end, encouraging students to compute the results themselves using the given scenarios.
Transcribed Image Text:## Permutations The fundamental counting principle is applied when the number of options goes down at each station. We will not use or test the formulas here, although it is in the book. ### Example and Exercise: **Scenario:** In a club of 12 people, in how many ways can a president, vice-president, and treasurer be selected if no person may have more than one office? The number of ways can be calculated as: \[ 12 \times 11 \times 10 = 1,320 \text{ ways} \] **Problem:** At the horse races (with ten horses competing), in how many ways can the top three places be selected? (Note that no horse may have more than one of the top three places!) The number of ways can be calculated by: \[ P \times VP \times T \] The permutations formula applied for the top three places in the race can be solved as: \[ 10 \times 9 \times 8 \] So, the number of ways the top three places can be selected is: \[ = \_\_\_\_\_ \times \_\_\_\_\_ \times \_\_\_\_\_ = \] ### Diagram Explanation: This exercise includes a blanks graph at the end, encouraging students to compute the results themselves using the given scenarios.
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Step 1

Permutation:

The number of different arrangements of ‘r’ elements from a set of‘n’ elements is denoted and given by,

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