At the beginning of a board game, players randomly select 3 cones from a group of 10 cones consisting of 6 green cones and 4 blue cones. Complete parts (a) through (d) below. (a) How many different selections are possible? The 3 cones can be selected in nothing different ways. (b) How many selections contain all green cones? There are nothing different selections if all 3 are green cones. (c) How many selections contain 2 green cones and 1 blue cone? There are nothing different selections which contain 2 green cones and 1 blue cone. (d) How many selections would include at least 1 blue cone? There are nothing different selections which contain at least 1 blue cone
Permutations and Combinations
If there are 5 dishes, they can be relished in any order at a time. In permutation, it should be in a particular order. In combination, the order does not matter. Take 3 letters a, b, and c. The possible ways of pairing any two letters are ab, bc, ac, ba, cb and ca. It is in a particular order. So, this can be called the permutation of a, b, and c. But if the order does not matter then ab is the same as ba. Similarly, bc is the same as cb and ac is the same as ca. Here the list has ab, bc, and ac alone. This can be called the combination of a, b, and c.
Counting Theory
The fundamental counting principle is a rule that is used to count the total number of possible outcomes in a given situation.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps