At STP, what is the mass 13.0 L of methane, CH4? O 27.6 g 16.0 g 0.580 g O 9.31 g

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**Question:**

At STP, what is the mass of 13.0 L of methane, CH₄?

**Options:**

- ○ 27.6 g
- ○ 16.0 g
- ○ 0.580 g
- ● 9.31 g

**Solution Explanation:**

At Standard Temperature and Pressure (STP), one mole of any ideal gas occupies 22.4 liters. Methane (CH₄) has a molar mass of approximately 16.04 g/mol.

To find the mass of methane:

1. Calculate the number of moles of CH₄ in 13.0 L at STP:
   \[
   \text{Moles of CH₄} = \frac{13.0 \, \text{L}}{22.4 \, \text{L/mol}} \approx 0.580 \, \text{mol}
   \]

2. Calculate the mass of 0.580 moles of CH₄:
   \[
   \text{Mass of CH₄} = 0.580 \, \text{mol} \times 16.04 \, \text{g/mol} \approx 9.31 \, \text{g}
   \]

Thus, the correct answer is **9.31 g**.
Transcribed Image Text:**Question:** At STP, what is the mass of 13.0 L of methane, CH₄? **Options:** - ○ 27.6 g - ○ 16.0 g - ○ 0.580 g - ● 9.31 g **Solution Explanation:** At Standard Temperature and Pressure (STP), one mole of any ideal gas occupies 22.4 liters. Methane (CH₄) has a molar mass of approximately 16.04 g/mol. To find the mass of methane: 1. Calculate the number of moles of CH₄ in 13.0 L at STP: \[ \text{Moles of CH₄} = \frac{13.0 \, \text{L}}{22.4 \, \text{L/mol}} \approx 0.580 \, \text{mol} \] 2. Calculate the mass of 0.580 moles of CH₄: \[ \text{Mass of CH₄} = 0.580 \, \text{mol} \times 16.04 \, \text{g/mol} \approx 9.31 \, \text{g} \] Thus, the correct answer is **9.31 g**.
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