At some point during their orbit, the location of the Earth and Moon relative to the Sun will be as shown in the figure below, with the Moon at the origin of the coordinate system, r. = (-3.84 x 10°j) m and r. = (-1.50 x 1011f) m. The mass of the Moon is 7.35 x 1022 kg, the Earth has a mass 5.97 x 1024 kg, and the Sun has a mass 2.00 x 1030 kg. What is the force experienced by the Moon due to the Sun and the Earth? Express your answer in vector form. net
At some point during their orbit, the location of the Earth and Moon relative to the Sun will be as shown in the figure below, with the Moon at the origin of the coordinate system, r. = (-3.84 x 10°j) m and r. = (-1.50 x 1011f) m. The mass of the Moon is 7.35 x 1022 kg, the Earth has a mass 5.97 x 1024 kg, and the Sun has a mass 2.00 x 1030 kg. What is the force experienced by the Moon due to the Sun and the Earth? Express your answer in vector form. net
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter7: Gravity
Section: Chapter Questions
Problem 64PQ
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Question
![### Gravitational Forces in the Earth-Moon-Sun System
At some point during their orbit, the location of the Earth and Moon relative to the Sun will be as shown in the figure below, with the Moon at the origin of the coordinate system.
Given data:
- Position of the Sun relative to Moon:
\[
\vec{r_s} = \left( -1.50 \times 10^{11} \right) \, \mathbf{\hat{i}} \, \text{m}
\]
- Position of the Earth relative to Moon:
\[
\vec{r_e} = \left( -3.84 \times 10^{8} \right) \, \mathbf{\hat{j}} \, \text{m}
\]
- Mass of the Moon:
\[
7.35 \times 10^{22} \, \text{kg}
\]
- Mass of the Earth:
\[
5.97 \times 10^{24} \, \text{kg}
\]
- Mass of the Sun:
\[
2.00 \times 10^{30} \, \text{kg}
\]
**Objective:**
Determine the force experienced by the Moon due to the Sun and the Earth. Express your answer in vector form.
**Illustration:**
The diagram below shows the relative positions and distances among the Sun, Earth, and Moon. The Moon is positioned at the origin (0,0) of the coordinate system.
#### Diagram Description
- **Sun** is located at a position vector \( \vec{r_s} \) directed along the negative x-axis (left side).
- **Earth** is located at a position vector \( \vec{r_e} \) directed along the negative y-axis (downward).
\[
\begin{array}{c}
\text{Sun} \xleftarrow{\quad \vec{r_s} \quad} Moon \, (0, 0) \xotherdirection{\quad \vec{r_e} \quad} \downarrow Earth \\
\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\
\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd0afef86-41bd-49f7-9deb-bb70dd2f5172%2Fe3957ecd-e89b-406a-a416-e2e54741dbe7%2F8vpwnkc.png&w=3840&q=75)
Transcribed Image Text:### Gravitational Forces in the Earth-Moon-Sun System
At some point during their orbit, the location of the Earth and Moon relative to the Sun will be as shown in the figure below, with the Moon at the origin of the coordinate system.
Given data:
- Position of the Sun relative to Moon:
\[
\vec{r_s} = \left( -1.50 \times 10^{11} \right) \, \mathbf{\hat{i}} \, \text{m}
\]
- Position of the Earth relative to Moon:
\[
\vec{r_e} = \left( -3.84 \times 10^{8} \right) \, \mathbf{\hat{j}} \, \text{m}
\]
- Mass of the Moon:
\[
7.35 \times 10^{22} \, \text{kg}
\]
- Mass of the Earth:
\[
5.97 \times 10^{24} \, \text{kg}
\]
- Mass of the Sun:
\[
2.00 \times 10^{30} \, \text{kg}
\]
**Objective:**
Determine the force experienced by the Moon due to the Sun and the Earth. Express your answer in vector form.
**Illustration:**
The diagram below shows the relative positions and distances among the Sun, Earth, and Moon. The Moon is positioned at the origin (0,0) of the coordinate system.
#### Diagram Description
- **Sun** is located at a position vector \( \vec{r_s} \) directed along the negative x-axis (left side).
- **Earth** is located at a position vector \( \vec{r_e} \) directed along the negative y-axis (downward).
\[
\begin{array}{c}
\text{Sun} \xleftarrow{\quad \vec{r_s} \quad} Moon \, (0, 0) \xotherdirection{\quad \vec{r_e} \quad} \downarrow Earth \\
\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\
\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad
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