### Gravitational Forces in the Earth-Moon-Sun SystemAt some point during their orbit, the location of the Earth and Moon relative to the Sun will be as shown in the figure below, with the Moon at the origin of the coordinate system.Given data:- Position of the Sun relative to Moon: \[ \vec{r_s} = \left( -1.50 \times 10^{11} \right) \, \mathbf{\hat{i}} \, \text{m} \]- Position of the Earth relative to Moon: \[ \vec{r_e} = \left( -3.84 \times 10^{8} \right) \, \mathbf{\hat{j}} \, \text{m} \]- Mass of the Moon: \[ 7.35 \times 10^{22} \, \text{kg} \]- Mass of the Earth: \[ 5.97 \times 10^{24} \, \text{kg} \]- Mass of the Sun: \[ 2.00 \times 10^{30} \, \text{kg} \]**Objective:**Determine the force experienced by the Moon due to the Sun and the Earth. Express your answer in vector form.**Illustration:**The diagram below shows the relative positions and distances among the Sun, Earth, and Moon. The Moon is positioned at the origin (0,0) of the coordinate system.#### Diagram Description- **Sun** is located at a position vector \( \vec{r_s} \) directed along the negative x-axis (left side).- **Earth** is located at a position vector \( \vec{r_e} \) directed along the negative y-axis (downward).\[\begin{array}{c}\text{Sun} \xleftarrow{\quad \vec{r_s} \quad} Moon \, (0, 0) \xotherdirection{\quad \vec{r_e} \quad} \downarrow Earth \\\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad

Answered: Image /qna-images/answer/e3957ecd-e89b-406a-a416-e2e54741dbe7.jpg

At some point during their orbit, the location of the Earth and Moon relative to the Sun will be as shown in the figure below, with the Moon at the origin of the coordinate system, r. = (-3.84 x 10°j) m and r. = (-1.50 x 1011f) m. The mass of the Moon is 7.35 x 1022 kg, the Earth has a mass 5.97 x 1024 kg, and the Sun has a mass 2.00 x 1030 kg. What is the force experienced by the Moon due to the Sun and the Earth? Express your answer in vector form. net

At some point during their orbit, the location of the Earth and Moon relative to the Sun will be as shown in the figure below, with the Moon at the origin of the coordinate system, r. = (-3.84 x 10°j) m and r. = (-1.50 x 1011f) m. The mass of the Moon is 7.35 x 1022 kg, the Earth has a mass 5.97 x 1024 kg, and the Sun has a mass 2.00 x 1030 kg. What is the force experienced by the Moon due to the Sun and the Earth? Express your answer in vector form. net

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

### Gravitational Forces in the Earth-Moon-Sun System

At some point during their orbit, the location of the Earth and Moon relative to the Sun will be as shown in the figure below, with the Moon at the origin of the coordinate system.

Given data:
- Position of the Sun relative to Moon:
\[
\vec{r_s} = \left( -1.50 \times 10^{11} \right) \, \mathbf{\hat{i}} \, \text{m}
\]

- Position of the Earth relative to Moon:
\[
\vec{r_e} = \left( -3.84 \times 10^{8} \right) \, \mathbf{\hat{j}} \, \text{m}
\]

- Mass of the Moon:
\[
7.35 \times 10^{22} \, \text{kg}
\]

- Mass of the Earth:
\[
5.97 \times 10^{24} \, \text{kg}
\]

- Mass of the Sun:
\[
2.00 \times 10^{30} \, \text{kg}
\]

**Objective:**
Determine the force experienced by the Moon due to the Sun and the Earth. Express your answer in vector form.

**Illustration:**
The diagram below shows the relative positions and distances among the Sun, Earth, and Moon. The Moon is positioned at the origin (0,0) of the coordinate system.

#### Diagram Description
- **Sun** is located at a position vector \( \vec{r_s} \) directed along the negative x-axis (left side).
- **Earth** is located at a position vector \( \vec{r_e} \) directed along the negative y-axis (downward).

\[
\begin{array}{c}
\text{Sun} \xleftarrow{\quad \vec{r_s} \quad} Moon \, (0, 0) \xotherdirection{\quad \vec{r_e} \quad} \downarrow Earth \\
\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\
\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad

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