At room temperature, a typical person loses energy to the surroundings at the rate of 62 W. If this energy loss has to be made up by an equivalent food intake, how many kilocalories (food calories) does this person need to consume every day just to make up this heat loss? (1 cal = 4.186 J) A) 1500 kcal B) 1600 kcal C) 1000 kcal D) 1100 kcal E) 1300 kcal
Energy transfer
The flow of energy from one region to another region is referred to as energy transfer. Since energy is quantitative; it must be transferred to a body or a material to work or to heat the system.
Molar Specific Heat
Heat capacity is the amount of heat energy absorbed or released by a chemical substance per the change in temperature of that substance. The change in heat is also called enthalpy. The SI unit of heat capacity is Joules per Kelvin, which is (J K-1)
Thermal Properties of Matter
Thermal energy is described as one of the form of heat energy which flows from one body of higher temperature to the other with the lower temperature when these two bodies are placed in contact to each other. Heat is described as the form of energy which is transferred between the two systems or in between the systems and their surrounding by the virtue of difference in temperature. Calorimetry is that branch of science which helps in measuring the changes which are taking place in the heat energy of a given body.
Please show all calculations and type them out since I have bad eyesight and it is very difficult for me to read handwriting
![### Heat Loss and Energy Intake Calculation
#### Problem Statement
At room temperature, a typical person loses energy to the surroundings at the rate of 62 W. If this energy loss has to be made up by an equivalent food intake, how many kilocalories (food calories) does this person need to consume every day just to make up this heat loss?
(Note: 1 cal = 4.186 J)
#### Options
A) 1500 kcal
B) 1600 kcal
C) 1000 kcal
D) 1100 kcal
E) 1300 kcal
#### Solution
To find the required energy intake, we need to calculate the total energy lost per day and then convert that into kilocalories.
1. **Energy Loss Calculation:**
- Power (P) = 62 W
- Time (t) = 24 hours/day
- Energy (E) can be calculated using the formula: \(E = P \times t\)
- Convert time to seconds (since 1 W = 1 J/s):
- 24 hours = 24 * 60 * 60 seconds = 86,400 seconds
Hence,
\[
E = 62 \ \text{W} \times 86,400 \ \text{seconds} = 5,356,800 \ \text{J}
\]
2. **Conversion to Kilocalories:**
- 1 calorie (cal) = 4.186 J
- 1 kilocalorie (kcal) = 1,000 calories
Therefore, converting joules to kilocalories:
\[
\text{Energy in kcal} = \frac{5,356,800 \ \text{J}}{4.186 \ \text{J/cal} \times 1,000 \ \text{cal/kcal}}
\]
\[
\text{Energy in kcal} \approx 1280 \ \text{kcal}
\]
#### Answer
The closest value from the given options is:
E) 1300 kcal](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6527be19-4214-4a2f-aca2-4f82253fbdd1%2F448e9090-048e-4955-9ccf-0813ac65d31d%2F2b9lpw_processed.png&w=3840&q=75)
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