At noon (t= 0), Alicia starts walking along a long, straight road at 4 mi/hr. Her velocity decreases according to the function v(t) = 4/(t + 1) for t2 0. At noon, Boris also starts walking along the same road with a 1-mi head start on Alicia; his velocity is given by u(t) = 2/(t + 1) for t20. %3D a. Find the position functions for Alicia and Boris, where s = 0 corresponds to Alicia's starting point. b. When, if ever, does Alicia overtake Boris? a. Alicia's position function is sA (t) = for t20.

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
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Chapter9: Functions
Section9.1: Relations And Functions
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At noon (t=0), Alicia starts walking along a long, straight road at 4 mi/hr. Her velocity decreases according to the
function v(t) = 4/(t+ 1) for t> 0. At noon, Boris also starts walking along the same road with a 1-mi head start on Alicia;
his velocity is given by u(t) = 2/(t+ 1) for t2 0.
a. Find the position functions for Alicia and Boris, where s = 0 corresponds to Alicia's starting point.
b. When, if ever, does Alicia overtake Boris?
a. Alicia's position function is s (t) =
for t>0.
Transcribed Image Text:At noon (t=0), Alicia starts walking along a long, straight road at 4 mi/hr. Her velocity decreases according to the function v(t) = 4/(t+ 1) for t> 0. At noon, Boris also starts walking along the same road with a 1-mi head start on Alicia; his velocity is given by u(t) = 2/(t+ 1) for t2 0. a. Find the position functions for Alicia and Boris, where s = 0 corresponds to Alicia's starting point. b. When, if ever, does Alicia overtake Boris? a. Alicia's position function is s (t) = for t>0.
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