At my local bar, it always takes at least two minutes to serve a customer, and it can take much longer. The time in minutes that it takes to serve a customer may be modelled by a continuous random variable T with probability density function f(t) 64 t≥ 2.

A First Course in Probability (10th Edition)
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Hi. Please help. I need to calculate the mean and vairance of the probabiltiy density function I am getting one minute but the time better each serving is at least 2 minutes. Can you correct me as I have gone wrong somewhere. (see attached doc)

At my local bar, it always takes at least two minutes to serve a customer, and it can take much
longer. The time in minutes that it takes to serve a customer may be modelled by a continuous
random variable T with probability density function
f(t) = 64, t> 2.
The C.d.f for random variable T is,
wwwwww
16
F(t) = 1- t> 2.
Use the p.d.f. f(t) to calculate the mean and variance of the time taken
to serve a customer.
Mean
u= E(T)
11
=
=
= √₂ + f (6) dt
11
=
64
dt
So 64E-5 alt
:(-16) - (-1²)
0 + 1
= 1 minute.
[-16] 2
= [-]일
AS
(im I
∞0 + 0
Transcribed Image Text:At my local bar, it always takes at least two minutes to serve a customer, and it can take much longer. The time in minutes that it takes to serve a customer may be modelled by a continuous random variable T with probability density function f(t) = 64, t> 2. The C.d.f for random variable T is, wwwwww 16 F(t) = 1- t> 2. Use the p.d.f. f(t) to calculate the mean and variance of the time taken to serve a customer. Mean u= E(T) 11 = = = √₂ + f (6) dt 11 = 64 dt So 64E-5 alt :(-16) - (-1²) 0 + 1 = 1 minute. [-16] 2 = [-]일 AS (im I ∞0 + 0
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