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The system of first order differential equations: has solution: y₁ (t) Y₂(t) - = Note: You must express the answer in terms of real numbers only. S3/1₁ ly/2 = = -8 y₁ + 2 y2, -52 yı + 12 y2, y₁ (0) Y₂ (0) = -4 = -25

The system of first order differential equations: has solution: y₁ (t) Y₂(t) - = Note: You must express the answer in terms of real numbers only. S3/1₁ ly/2 = = -8 y₁ + 2 y2, -52 yı + 12 y2, y₁ (0) Y₂ (0) = -4 = -25

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The system of first order differential equations: has solution: y₁ (t) Y₂(t) - = Note: You must express the answer in terms of real numbers only. S3/1₁ ly/2 = = -8 yı + 2 y2, -52 yı + 12 y2, y₁ (0) Y₂ (0) = -4 = -25
Transcribed Image Text:The system of first order differential equations: has solution: y₁ (t) Y₂(t) - = Note: You must express the answer in terms of real numbers only. S3/1₁ ly/2 = = -8 yı + 2 y2, -52 yı + 12 y2, y₁ (0) Y₂ (0) = -4 = -25
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has solution: y₁ (t) Y₂(t) Entered -[e^(2*t)]*[4*cos(2)*t+5*sin(2)*t] At least one of the answers above is NOT correct. = -[e^(2*t)]*[25*cos(2)*t+21*sin (2)*t] The system of first order differential equations: -e²t (4 cos 2t + 5 sin 2t) -e²t (25 cos 2t + 21 sin 2t) Note: You must express the answer in terms of real numbers only. Jy1₁1 ly/2 = = -8 y₁ + 2 y2, -52 yı + 12 y2, Answer Preview -e²t (4 cos(2)t + 5 sin (2)t) -e²t (25 cos (2)t + 21 sin(2)t) Y₁(0) = -4 Y₂(0) = -25 Result incorrect incorrect
Transcribed Image Text:has solution: y₁ (t) Y₂(t) Entered -[e^(2*t)]*[4*cos(2)*t+5*sin(2)*t] At least one of the answers above is NOT correct. = -[e^(2*t)]*[25*cos(2)*t+21*sin (2)*t] The system of first order differential equations: -e²t (4 cos 2t + 5 sin 2t) -e²t (25 cos 2t + 21 sin 2t) Note: You must express the answer in terms of real numbers only. Jy1₁1 ly/2 = = -8 y₁ + 2 y2, -52 yı + 12 y2, Answer Preview -e²t (4 cos(2)t + 5 sin (2)t) -e²t (25 cos (2)t + 21 sin(2)t) Y₁(0) = -4 Y₂(0) = -25 Result incorrect incorrect
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