At its peak, a tornado is 55.0 m in diameter and carries 505-km/h winds. What is its angular velocity in revolutions per second? rev/s

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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**Understanding Angular Velocity in Tornadoes**

At its peak, a tornado is **55.0 m** in diameter and carries **505-km/h** winds. What is its angular velocity in revolutions per second?

[Input Box]
- rev/s

---

**Explanation for Educational Context:**

This example focuses on calculating the angular velocity of a tornado. Angular velocity is the rate at which an object rotates or revolves and is a critical concept in physics, particularly when analyzing circular motion.

**Key Components:**

- **Diameter of Tornado:** 55.0 meters
- **Wind Speed:** 505 km/h

**Goal:**

Find the angular velocity, expressed in revolutions per second (rev/s), using the given diameter and wind speed information.
Transcribed Image Text:**Understanding Angular Velocity in Tornadoes** At its peak, a tornado is **55.0 m** in diameter and carries **505-km/h** winds. What is its angular velocity in revolutions per second? [Input Box] - rev/s --- **Explanation for Educational Context:** This example focuses on calculating the angular velocity of a tornado. Angular velocity is the rate at which an object rotates or revolves and is a critical concept in physics, particularly when analyzing circular motion. **Key Components:** - **Diameter of Tornado:** 55.0 meters - **Wind Speed:** 505 km/h **Goal:** Find the angular velocity, expressed in revolutions per second (rev/s), using the given diameter and wind speed information.
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