At i = 1 At i = 2 At i = 3 Y₂ − 1.9375y₁ + - 0.0625 = 0 Y3 1.9375y2 + y₁ -0.0625 = 0 - 1.9375y2 + ₁ - 0.0625 = 0
At i = 1 At i = 2 At i = 3 Y₂ − 1.9375y₁ + - 0.0625 = 0 Y3 1.9375y2 + y₁ -0.0625 = 0 - 1.9375y2 + ₁ - 0.0625 = 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
please show the solution for the answers in the box
Transcribed Image Text:At i = 1
At i = 2
At i = 3
Y2 1.9375y₁ +0.0625 = 0
-
Y3 1.9375y₂ + y₁ -0.0625 = 0
-
1.9375y₂ + Y₁ - 0.0625 = 0
Transcribed Image Text:Solve the system of linear equation to find y₁, Y2 ‚Y3.
Y₁ -0.1047
У1 =
Y₂ = 0.1403
Y3 = -0.1047
0
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