At high temperatures, nitrogen dioxide, NO2, decomposes into NO and O₂. If y() is the concentration of NO₂ (in moles per liter), then at 600 K, y(t) changes according to the reaction law =-.05y² for timer in seconds. A. Express y in terms of and the initial concentration y.. B. Assuming that the concentration of NO₂ is twice as high at = 20 seconds as it is at 100 seconds, find the exact initial concentration of the NO2. Reminder: "Exact" means no calculator numbers.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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4. At high temperatures, nitrogen dioxide, NO,, decomposes into NO and 02. If yO is the
concentration of NO, (in moles per liter), then at 600°K, y(1) changes according to tne
reaction law = -.05y² for time r in seconds.
A. Express y in terms of i and the initial concentration y..
B. Assuming that the concentration of NO, is twice as high at i = 20 seconds as it is at 100
seconds, find the exact initial concentration of the NO2. Reminder: "Exact" means no
calculator numbers.
Transcribed Image Text:4. At high temperatures, nitrogen dioxide, NO,, decomposes into NO and 02. If yO is the concentration of NO, (in moles per liter), then at 600°K, y(1) changes according to tne reaction law = -.05y² for time r in seconds. A. Express y in terms of i and the initial concentration y.. B. Assuming that the concentration of NO, is twice as high at i = 20 seconds as it is at 100 seconds, find the exact initial concentration of the NO2. Reminder: "Exact" means no calculator numbers.
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