At her local market, Joanna purchases a regular-size can of tomato paste. The cylindrical can has a radius of 2 cm and a height of 5 cm. At the warehouse club, she sees a value-size can of tomato paste that contains 4 times as much tomato paste as the regular size. Which of these could be the dimensions of the cylindrical value-size can? radius = 8 cm, height = 20 cm B.O radius = 4 cm, height = 10 cm c.O radius = 4 cm, height = 5 cm D. radius = 16 cm, height = 5 cm

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem Description:**

At her local market, Joanna purchases a regular-size can of tomato paste. The cylindrical can has a radius of 2 cm and a height of 5 cm. At the warehouse club, she sees a value-size can of tomato paste that contains 4 times as much tomato paste as the regular size. Which of these could be the dimensions of the cylindrical value-size can?

**Answer Choices:**

A. radius = 8 cm, height = 20 cm  
B. radius = 4 cm, height = 10 cm  
C. radius = 4 cm, height = 5 cm  
D. radius = 16 cm, height = 5 cm  

### Explanation and Solution:

To determine which of these dimensions could be the value-size can, we need to compare their volumes relative to the regular-size can.

**Step-by-Step Solution:**

1. **Calculate the volume of the regular-size can:**

   The volume of a cylinder is given by the formula:
   \[
   V = \pi r^2 h
   \]
   For the regular-size can:
   \[
   r = 2 \, \text{cm}, \quad h = 5 \, \text{cm}
   \]
   Substitute the values into the formula:
   \[
   V = \pi (2)^2 (5) = 20\pi \, \text{cm}^3
   \]

2. **Determine the volume of the value-size can:**

   The value-size can contains 4 times as much tomato paste as the regular-size can. Thus, its volume is:
   \[
   4 \times 20\pi = 80\pi \, \text{cm}^3
   \]

3. **Check each answer choice by calculating the volume:**

   - **Option A: radius = 8 cm, height = 20 cm**
     \[
     V = \pi (8)^2 (20) = 1280\pi \, \text{cm}^3 \quad \text{(not equal to } 80\pi \text{)}
     \]

   - **Option B: radius = 4 cm, height = 10 cm**
     \[
     V = \pi (4)^2 (10) = 160\pi \, \text{cm}^3 \quad \text
Transcribed Image Text:**Problem Description:** At her local market, Joanna purchases a regular-size can of tomato paste. The cylindrical can has a radius of 2 cm and a height of 5 cm. At the warehouse club, she sees a value-size can of tomato paste that contains 4 times as much tomato paste as the regular size. Which of these could be the dimensions of the cylindrical value-size can? **Answer Choices:** A. radius = 8 cm, height = 20 cm B. radius = 4 cm, height = 10 cm C. radius = 4 cm, height = 5 cm D. radius = 16 cm, height = 5 cm ### Explanation and Solution: To determine which of these dimensions could be the value-size can, we need to compare their volumes relative to the regular-size can. **Step-by-Step Solution:** 1. **Calculate the volume of the regular-size can:** The volume of a cylinder is given by the formula: \[ V = \pi r^2 h \] For the regular-size can: \[ r = 2 \, \text{cm}, \quad h = 5 \, \text{cm} \] Substitute the values into the formula: \[ V = \pi (2)^2 (5) = 20\pi \, \text{cm}^3 \] 2. **Determine the volume of the value-size can:** The value-size can contains 4 times as much tomato paste as the regular-size can. Thus, its volume is: \[ 4 \times 20\pi = 80\pi \, \text{cm}^3 \] 3. **Check each answer choice by calculating the volume:** - **Option A: radius = 8 cm, height = 20 cm** \[ V = \pi (8)^2 (20) = 1280\pi \, \text{cm}^3 \quad \text{(not equal to } 80\pi \text{)} \] - **Option B: radius = 4 cm, height = 10 cm** \[ V = \pi (4)^2 (10) = 160\pi \, \text{cm}^3 \quad \text
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