please help answer thank you in advance. Atexactly two of the labeled points in the figure below, which shows a function f, the derivative f' is zero; the second derivative f" is notny of the labeled points. Select the correct signs for each of ƒ,ƒ' and ƒ" at each marked point.Pointf?ƒ' ?f"?A???B←B?????◆ ?D???E◄►◄►

The figure given is If the graph of f(x) is above the x-axis then f(x)>0 and if the graph of f(x) is below the x-axis then f(x)<0. Also, if the graph cut the x-axis then f(x) = 0 If the function is increasing then f'(x)>0 and if the function is decreasing then f'(x)<0 If the function is concave up then f''(x)>0 and if the function is concave downward then f''(x)<0 At point A, the graph cut the x-axis, decreasing and concaving upward. So at point A, f(x)=0, f'(x)<0, f''(x)>0 At point B, the graph is above the x-axis, has a local maximum, and is concave downward. So at point B, f(x)>0, f'(x)=0, f''(x)<0 At point C, the graph is below the x-axis, decreasing, and concave upward. So at point C, f(x)<0, f'(x)<0, f''(x)>0 At point D, the graph is below the x-axis, has a local minimum, and is concave upward. So at point D, f(x)<0, f'(x)=0, f''(x)>0 At point E, the graph is below the x-axis, increasing, and concave upward. So at point E, f(x)<0, f'(x)>0, f''(x)>0 Therefore, Function/Point A B C D E f =0 > 0 < 0 < 0 < 0 f' < 0 = 0 < 0 = 0 > 0 f" > 0 < 0 > 0 > 0 > 0