At constant volume, the temperature of a sample of sulfur dioxide gas is decreased from 97 oC to 27 o What was the original pressure of the gas, in atmospheres, if this action decreases the sample pressure to 3.00 atm?

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  1. At constant volume, the temperature of a sample of sulfur dioxide gas is decreased from 97 oC to 27 o What was the original pressure of the gas, in atmospheres, if this action decreases the sample pressure to 3.00 atm?

 

**Gas Law Problem**

At constant volume, the temperature of a sample of sulfur dioxide gas is decreased from 97°C to 27°C. What was the original pressure of the gas, in atmospheres, if this action decreases the sample pressure to 3.00 atm?

*Note*: This problem can be solved using the ideal gas law relationship, where pressure and temperature are directly proportional when volume and the number of moles are constant. Use the formula:

\[ \frac{P_1}{T_1} = \frac{P_2}{T_2} \]

where \( P_1 \) and \( P_2 \) are the initial and final pressures, respectively, and \( T_1 \) and \( T_2 \) are the initial and final temperatures in Kelvin. Remember to convert Celsius to Kelvin by adding 273.15.
Transcribed Image Text:**Gas Law Problem** At constant volume, the temperature of a sample of sulfur dioxide gas is decreased from 97°C to 27°C. What was the original pressure of the gas, in atmospheres, if this action decreases the sample pressure to 3.00 atm? *Note*: This problem can be solved using the ideal gas law relationship, where pressure and temperature are directly proportional when volume and the number of moles are constant. Use the formula: \[ \frac{P_1}{T_1} = \frac{P_2}{T_2} \] where \( P_1 \) and \( P_2 \) are the initial and final pressures, respectively, and \( T_1 \) and \( T_2 \) are the initial and final temperatures in Kelvin. Remember to convert Celsius to Kelvin by adding 273.15.
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