### Educational Resource: Understanding Capacitors in Electronic Circuits#### Experimental Observation: Capacitor Substitution and LED Illumination**Scenario:**In STEP 3, you replaced the 10μF capacitor at C1 with a 100μF capacitor and then observed the charging time of the larger capacitor. You should have seen that D1 was lit for much longer when charging the larger capacitor than when charging the smaller capacitor. How is this best explained?**Explanation Choices:**1. **Option A:** - *Statement:* My LED lit for about the same amount of time. I did not go back and change my circuit or try to figure out why the results were not as expected. - *Explanation:* This suggests no difference in observation, possibly due to a misunderstanding or an overlooked step in the experiment.2. **Option B:** - *Statement:* The 100μF capacitor is approximately ten times more powerful than the 10μF capacitor, enabling it to light the LED for a longer period of time. - *Explanation:* While this implies a direct proportionality in "power," it inaccurately reflects how capacitors work despite the intuition that more capacitance means more stored energy.3. **Option C:** - *Statement:* The size of the capacitor makes no real difference in the circuit. The larger capacitor has a higher maximum, leaving extra “capacity” after the same amount of electrical energy is stored. - *Explanation:* This inaccurately states that the capacitor's size does not significantly impact the circuit performance, which contradicts empirical observation.4. **Option D:** - *Statement:* The larger capacitor holds more electrical energy at the same voltage than the smaller capacitor. With the same current flowing, storing more electrical energy takes more time. - *Explanation:* This accurately explains the observed phenomenon. A 100μF capacitor, being larger, stores more electrical energy (due to its greater capacitance) than a 10μF capacitor when charged to the same voltage. Thus, it takes longer to charge and discharge, resulting in the LED staying lit for a longer period.**Conclusion:**The most accurate explanation is** Option D**, as it correctly describes how a capacitor’s capacity to store electrical energy influences the duration for which an LED stays lit. The larger 100μF capacitor stores more energy and, during discharge, provides that energy over a longer time span compared to the smaller **Description of the Simple LED Circuit****Components:**1. **Power Supply Battery (PSB)**: Provides a constant voltage of 3.3V.2. **Switch (SW1)**: A push-button switch for controlling the circuit.3. **Capacitor (C1)**: Stores electrical energy, rated at 100 µF.4. **Resistor (R1)**: Limits the current flow, valued at 10 kΩ.5. **Light Emitting Diode (D1)**: Emits red light when current flows through it.**Circuit Explanation:**This circuit is designed to control an LED using a simple switch. Here’s how it works:1. **Power Source (PSB 3.3V)**: The circuit is powered by a 3.3V direct current (DC) power supply. 2. **Switch (SW1)**: The switch (SW1) is used to control the flow of current to the LED. When the switch is closed (pressed), the circuit is completed and current flows through the circuit, lighting up the LED.3. **Capacitor (C1)**: The capacitor in the circuit is rated at 100 microfarads (µF). It smooths out any fluctuations in the voltage and stores energy. 4. **Resistor (R1)**: The resistor is rated at 10 kilo-ohms (kΩ). It limits the current flowing through the circuit to protect the LED from high current which might damage it.5. **LED (D1)**: The Light Emitting Diode in this circuit is red. When current flows through it, it emits red light. The direction of the LED is important; it must be connected with the correct polarity. The anode (positive) is connected to the switch, and the cathode (negative) side to the resistor.**Operation:**- When the switch is open, the circuit is incomplete, and no current flows, so the LED remains off.- When the switch is pressed, it closes the circuit, allowing current to flow from the power source, through the capacitor, the resistor, and then the LED.- The resistor ensures that the current is within safe limits for the LED.- The capacitor might also help to smooth out any fluctuations in the power supply, ensuring a steady current to the LED.**Diagram Explanation:**In the provided schematic:- The power source

Led and Capacitor and Resistor are connected in series So now we have to tell about reason why led…

at C1 with a 100µF capacitor and then observed the charging time of the rger capacitor. You should have seen that D1 was lit for much longer when charging the larger capacitor than when arging the smaller capacitor. How is this best explained? My LED lit for about the same amount of time. I did not go back and change my circuit or try to figure out why the results were not as expected. The 100µF capacitor is approximately ten times more powerful than the 10µF capacitor, enabling it to light the LED for a longer period of time. The size of the capacitor makes no real difference in the circuit. The larger capacitor has a higher maximum, leaving extra "capacity" after the same amount of electrical energy is stored. The larger capacitor holds more electrical energy at the same voltage than the smaller capacitor. With the same current flowing, storing more electrical energy takes more time.

at C1 with a 100µF capacitor and then observed the charging time of the rger capacitor. You should have seen that D1 was lit for much longer when charging the larger capacitor than when arging the smaller capacitor. How is this best explained? My LED lit for about the same amount of time. I did not go back and change my circuit or try to figure out why the results were not as expected. The 100µF capacitor is approximately ten times more powerful than the 10µF capacitor, enabling it to light the LED for a longer period of time. The size of the capacitor makes no real difference in the circuit. The larger capacitor has a higher maximum, leaving extra "capacity" after the same amount of electrical energy is stored. The larger capacitor holds more electrical energy at the same voltage than the smaller capacitor. With the same current flowing, storing more electrical energy takes more time.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Please answer with explanation. I will really upvote