### Educational Resource: Understanding Capacitors in Electronic Circuits#### Experimental Observation: Capacitor Substitution and LED Illumination**Scenario:**In STEP 3, you replaced the 10μF capacitor at C1 with a 100μF capacitor and then observed the charging time of the larger capacitor. You should have seen that D1 was lit for much longer when charging the larger capacitor than when charging the smaller capacitor. How is this best explained?**Explanation Choices:**1. **Option A:** - *Statement:* My LED lit for about the same amount of time. I did not go back and change my circuit or try to figure out why the results were not as expected. - *Explanation:* This suggests no difference in observation, possibly due to a misunderstanding or an overlooked step in the experiment.2. **Option B:** - *Statement:* The 100μF capacitor is approximately ten times more powerful than the 10μF capacitor, enabling it to light the LED for a longer period of time. - *Explanation:* While this implies a direct proportionality in "power," it inaccurately reflects how capacitors work despite the intuition that more capacitance means more stored energy.3. **Option C:** - *Statement:* The size of the capacitor makes no real difference in the circuit. The larger capacitor has a higher maximum, leaving extra “capacity” after the same amount of electrical energy is stored. - *Explanation:* This inaccurately states that the capacitor's size does not significantly impact the circuit performance, which contradicts empirical observation.4. **Option D:** - *Statement:* The larger capacitor holds more electrical energy at the same voltage than the smaller capacitor. With the same current flowing, storing more electrical energy takes more time. - *Explanation:* This accurately explains the observed phenomenon. A 100μF capacitor, being larger, stores more electrical energy (due to its greater capacitance) than a 10μF capacitor when charged to the same voltage. Thus, it takes longer to charge and discharge, resulting in the LED staying lit for a longer period.**Conclusion:**The most accurate explanation is** Option D**, as it correctly describes how a capacitor’s capacity to store electrical energy influences the duration for which an LED stays lit. The larger 100μF capacitor stores more energy and, during discharge, provides that energy over a longer time span compared to the smaller **Description of the Simple LED Circuit****Components:**1. **Power Supply Battery (PSB)**: Provides a constant voltage of 3.3V.2. **Switch (SW1)**: A push-button switch for controlling the circuit.3. **Capacitor (C1)**: Stores electrical energy, rated at 100 µF.4. **Resistor (R1)**: Limits the current flow, valued at 10 kΩ.5. **Light Emitting Diode (D1)**: Emits red light when current flows through it.**Circuit Explanation:**This circuit is designed to control an LED using a simple switch. Here’s how it works:1. **Power Source (PSB 3.3V)**: The circuit is powered by a 3.3V direct current (DC) power supply. 2. **Switch (SW1)**: The switch (SW1) is used to control the flow of current to the LED. When the switch is closed (pressed), the circuit is completed and current flows through the circuit, lighting up the LED.3. **Capacitor (C1)**: The capacitor in the circuit is rated at 100 microfarads (µF). It smooths out any fluctuations in the voltage and stores energy. 4. **Resistor (R1)**: The resistor is rated at 10 kilo-ohms (kΩ). It limits the current flowing through the circuit to protect the LED from high current which might damage it.5. **LED (D1)**: The Light Emitting Diode in this circuit is red. When current flows through it, it emits red light. The direction of the LED is important; it must be connected with the correct polarity. The anode (positive) is connected to the switch, and the cathode (negative) side to the resistor.**Operation:**- When the switch is open, the circuit is incomplete, and no current flows, so the LED remains off.- When the switch is pressed, it closes the circuit, allowing current to flow from the power source, through the capacitor, the resistor, and then the LED.- The resistor ensures that the current is within safe limits for the LED.- The capacitor might also help to smooth out any fluctuations in the power supply, ensuring a steady current to the LED.**Diagram Explanation:**In the provided schematic:- The power source

Led and Capacitor and Resistor are connected in series So now we have to tell about reason why led…

at C1 with a 100µF capacitor and then observed the charging time of the rger capacitor. You should have seen that D1 was lit for much longer when charging the larger capacitor than when arging the smaller capacitor. How is this best explained? My LED lit for about the same amount of time. I did not go back and change my circuit or try to figure out why the results were not as expected. The 100µF capacitor is approximately ten times more powerful than the 10µF capacitor, enabling it to light the LED for a longer period of time. The size of the capacitor makes no real difference in the circuit. The larger capacitor has a higher maximum, leaving extra "capacity" after the same amount of electrical energy is stored. The larger capacitor holds more electrical energy at the same voltage than the smaller capacitor. With the same current flowing, storing more electrical energy takes more time.

at C1 with a 100µF capacitor and then observed the charging time of the rger capacitor. You should have seen that D1 was lit for much longer when charging the larger capacitor than when arging the smaller capacitor. How is this best explained? My LED lit for about the same amount of time. I did not go back and change my circuit or try to figure out why the results were not as expected. The 100µF capacitor is approximately ten times more powerful than the 10µF capacitor, enabling it to light the LED for a longer period of time. The size of the capacitor makes no real difference in the circuit. The larger capacitor has a higher maximum, leaving extra "capacity" after the same amount of electrical energy is stored. The larger capacitor holds more electrical energy at the same voltage than the smaller capacitor. With the same current flowing, storing more electrical energy takes more time.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

A certain parallel-plate capacitor has plate length of 2 cm and width of 3 cm. The dielectric has a thickness of 0.1 mm and a relative dielectric constant of 80. Determine the capacitance.
25 What charge is on a 5-F capacitor when it is connected across a 120-V source? 24 C none from the choices 300 C 600 C O 12 C
Q5: Two capacitors (2#F, 8 #F) are connected in series across 100 volt. Then these capacitors are connected in parallel. How much the charge for two cases. 06: Capacitor 20 HF is connecting with 55 volt, 50 Hz. Calculate the current for the capacitor. When this capacitor is connecting with 10 volt, 50 Hz. How much is the current.
Three 20uF capacitors are connected in series with each other. A 1k ohm resistor and an LED connected in series to each other as well, but branched in parallel to all three capacitors. How long would the LED stay lit after power is removed? What current would flow through it during the charge cycle if VT=9v?
r cut 1oum 20gm 1ocm 个 //// wax poper/ A capacitur is mad by sandwiching a sheet of wax psper between two sheebs of aluminum fail, as shoumm What is the figue. capacitance! I the capacitoris aut into twopieces, alme the hme, what oil be the expacitenel of each Diece ? wiggly What lo be the capactnce
06: Capacitor 20 #F is connecting with 55 volt, 50 Hz. Calculate the current for the capacitor. When this capacitor is connecting with 10 volt, 50 Hz. How much is the current.
Determine the total capacitance, total charge, individual voltage drop and charges across across each capacitor. Use two decimal places for your answer. Please put your answer for the individual voltage and charge for each capacitor in a table for faster checking. Thank you! C1= 27 F C2= 53 F C3= 21 F C4= 50 F C5= 17 F C6= 22 F C7= 45 F C8= 16 F C9= 25 F C10= 16 F V= 110 V Note: This topic is under capacitors.
Calculate values of asked physical quantities of the circuit in the figure. What is the capacitance of system 23? C23 C₁ = 3.0 F What is the capacitance of system 123? C123 = F C₁ = 2.0 F What is the capacitance of system 45? C45 = F Your last answer was interpreted as follows: 1 Your last answer was interpreted as follows: 1 What is the charge in the capacitor system? C Your last answer was interpreted as follows: 1 What is the total capacitance of the system? F Value 8.8500 x 10 EO Quantity permittivity of free space capacitance capacitance capacitance capacitance capacitance Your last answer was interpreted as follows: 1 capacitance of system 23 capacitance of system 123 capacitance of system 45 Your last answer was interpreted as follows: 1 Do not leave any fields blank. If you don't know the answer, insert 1 for example. Insert the answer with 3 significant digits without rounding the answer. Constant U = 7.0 V Unit E Symbol €0 C₁ = 3.0 F C1 C₂ C3 C4 C5 C23 C₂ = 9.0 F C₂ = 3.0 F…
A 470- uF capacitor is connected in series with a 120-k2 resistor. How long will it take the capacitor to charge completely?
A capacitor has a reactance of 2k-ohm at a frequency of 2 kHz. What is the approximate value of capacitor?
Determine the total capacitance, total charge, individual voltage drop and charges across each capacitor. Use two decimal places for your answer. Put your answer for the individual voltage and charge for each capacitor in a table for faster checking. Thank you! Here are the values for the capacitors: C1 = 55 C6 = 50 C2 = 25 C7 = 17 C3 = 49 C8 = 44 C4 = 22 C9 = 53 C5 = 45 C10 = 44
Which of the following is correct for a diode ○ A diode conducts in a forward bias A diode conducts in a reverse bias ○ A diode can never conduct as it is an insulator all the time. OA diode is a bi-directional device.