At any point in space, the electric field E is defined to be in thedirection of the electric force on a positively charged particle at thatpoint. Why don’t we similarly define the magnetic field B to be in thedirection of the magnetic force on a moving, positively charged particle?
Q: (A) Determine the direction of the magnetic field for each case in the figure below, where F…
A: Since you have posted multiple questions, we will provide the solution only to the first question as…
Q: A charged particle (q) is shot with a velocity v in a straight line parallel to an external magnetic…
A: In general, Lorentz magnetic force is given by FB = qvBsinθ Where q is charge…
Q: A long solenoid with 13.8 turns/cm and a radius of 8.90 cm carries a current of 26.9 mA. A current…
A:
Q: e m Br
A:
Q: Consider an equilateral triangle, with side length 0.267 m. At two of the vertices of this triangle,…
A:
Q: Show (starting with fundamental physics principles) that a particle moving perpendicular to a…
A:
Q: A double-ionized helium atom, carrying charge +2e (a-particle) is moving with velocity v, that makes…
A: Given that the charge carried by the particle is +2e, e being the magnitude of electronic charge,…
Q: A charged particle with charge q and velocity v = vx + vy is moving into a region of space with…
A: Given data: A charged particle with charge is, q Velocity of the charge particle is, v = vx + vyv=…
Q: 1. Consider three particles moving in a magnetic field that is coming out of the page. (a) Are the…
A:
Q: Consider a magnetic field (B) with B = 2.20 x 104 T in a place on Earth surface, directed parallel…
A: Given : |B| = 2.20 × 10-4 T (North) L = 2.50 km = 2.50 × 103 m v = 6.5 km/s v= 6.5 × 103 m/s (East)
Q: The figure below shows the path of an electron in a region of uniform magnetic field B (into the…
A: The magnitude of the electric field, E=200 N/C The velocity of the electron, v=2×106 m/s The length…
Q: In 1932, Ernest Lawrence invented the cyclotron, in which a strong vertical magnetic field acted on…
A: In 1932, Ernest Lawrence invented the cyclotron, in which a strong vertical magnetic field acted on…
Q: a region where there is both an electric field E~ pointing upward (shown in the figure below), and…
A:
Q: The magnetic field in a region is given by B = (0.750 +0.210) T. At some instant, a particle with…
A:
Q: Sketch the magnetic field of a long, current-carrying wire, with the current going into the paper.…
A: Magnetic filed due to a straight current carrying conductor
Q: A point charge moving in a magnetic field of 1.24 Tesla experiences a force of 0.615E-11 N. The…
A: According to Lorentz Force F = q(E + v×B) And E is zero, So F = q(v×B) Now given that, magnetic…
Q: Sketch the magnetic field (using field lines) in the region surrounding a straight wire carrying a…
A: Magnetic field in the region surrounding a straight wire carrying a current can be drawn as:
Q: A positively charged particle, q, of mass m moves at a constant velocity along the x direction. The…
A: Drag Force: This force is exerted by the fluid on the object traveling through it and it opposes its…
Q: After being accelerated to a speed of 1.80×105 m/s, the particle enters a uniform magnetic field of…
A: The given data are: v=1.8×105 m/sB=0.8 Tr=30 cm=0.3 m Here, v, B,and r represent the speed, magnetic…
Q: Consider an equilateral triangle, with side length 0.477 m. At two of the vertices of this triangle,…
A:
Q: A 1.6 m long straight horizontal wire carrying a current of 5.3 A along the +x-direction is in a…
A:
Q: An electron moving at 3.95 × 103 m/s in a 1.05 T magnetic field experiences a magnetic force of 1.4…
A: Given data: Velocity (v) = 3.95×103 m/s Magnetic field (B) = 1.05 T Magnetic force (F) = 1.4×10-16…
Q: A particle with unit charge (q= 1) enters a constant magnetic field B=i+j with velocity v = 21k.…
A:
Q: A 50 g ball cointaining 406779288 excess electrons is dropped into a 122m vertical shaft and enters…
A: Given data, mass of the ball (m)=50 g Number of electron(n)=406779288 Depth of the shaft(h)=122 m…
At any point in space, the electric field E is defined to be in the
direction of the electric force on a positively charged particle at that
point. Why don’t we similarly define the magnetic field B to be in the
direction of the magnetic force on a moving, positively charged particle?
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
- Due Wednesday 7/12 Problem 1. An infinitely long straight wire carries a current / 1.0 A that flows in the positive à direction. The external magnetic field at position along the wire is given by B(r) Boe / where Bo 110 mT and a 0.15 m. What is the force F on the wire due to this external magnetic field?A singularly-charged ion (i.e. a neutral atom which has gained one electron) with kinetic energy of 7x10−15 J follows a circular path of radius 0.6m when placed in a magnetic field of 0.5T. (Note that the charge of an electron is e = 1.6 x 10−19 C.) a) Using the fact that the ion is going in a circular motion in a magnetic field, what is the ion’s momentum (in kg.m/s)? b) What is the ion’s speed (in m/s)? c) What is the ion’s mass (in kg)? d) An electric field is added to the experiment and adjusted so that the ion passes through without any deflection. What is the magnitude of this electric field (in T)?An electron is launched at a speed of v at an angle of 0 north of east into a region with a uniform magnetic field. The magnitude of the magnetic field is B and the field is pointing due east. a) Find the radius of curvature of the trajectory. b) Find the pitch (the distance traveled during one revolution, perpendicular to the plane of circular motion) of the trajectory.
- Diamagnets have the property that they "dampen" the effects of an external magnetic field by creating an opposing magnetic field. The diamagnet thus has an induced dipole moment that is anti- aligned, such that the induced north pole is closer to the north pole creating the external field. An application of this is that diamagnets can be levitated 2. Now, the mathematics of generally describing a force by a non-uniform field on a dipole is a little beyond the scope of this course, but we can still work through an approximation based on energy. Essentially, whenever the theoretical loss of gravitational potential energy from "falling" no longer can "pay the cost" of increasing the magnetic potential energy, the object no longer wants to fall. Suppose a diamagnetic object floats above the levitator where the magnitude of the magnetic field is 12 T, which is inducing" a magnetic dipole moment of 4.6 LA - m² in the object. The magnetic field 1.9 mm below the object is stronger with a…A long straight wire suspended in the air carries a conventional current of 7 amperes in the -x direction as shown (the wire runs along the x-axis). At a particular instant an electron at location m has velocity m/s. z out (a) What is the magnetic field due to the wire at the location of the electron? B = tesla (b) What is the magnetic force on the electron due to the current in the wire? F= N (c) If the moving particle were a proton instead of an electron, what would the magnetic force on the proton be? F =Calculate the velocity of a particle with charge qp=1.6×10−19qp=1.6×10−19 that moves at right angles to the direction of a uniform magnetic field of strength 57.2 mT , if the magnetic force on particle is 4×10−134×10−13 N. Give your answer in km s-1.
- Write down an expression for the force experienced by an electron moving with a velocity, v, in a magnetic field B. By equating this expression to the force required to cause electrons to follow a circular path of radius, r, derive an expression for the ratio, (?⁄?) for an electron in terms of the magnetic field strength, the radius of the circular path and the accelerating potential, V.Which describes the net force on a magnetic dipole in a uniform magnetic field? The net force vector is in the direction of the magnetic field. O The net force vector is in the direction opposite that of the magnetic field. The net force vector is perpendicular to the direction of the magnetic field. O The net force vector is zero.