At another local coffee shop, wait times for a cup of plain coffee are normally distributed with a mean of 125 seconds and a standard deviation of 22 seconds. a. What percentage of wait times for a cup of plain coffee are less than 90 seconds? Round the percentage to two decimal places. x % 0.0 b. What percentage of wait times for a cup of plain coffee are greater than 125 seconds? 50 c. What percentage of wait times for a cup of plain coffee are between 90 seconds and 125 seconds? Round your answer to two decimal places. 44.41 X%
At another local coffee shop, wait times for a cup of plain coffee are normally distributed with a mean of 125 seconds and a standard deviation of 22 seconds. a. What percentage of wait times for a cup of plain coffee are less than 90 seconds? Round the percentage to two decimal places. x % 0.0 b. What percentage of wait times for a cup of plain coffee are greater than 125 seconds? 50 c. What percentage of wait times for a cup of plain coffee are between 90 seconds and 125 seconds? Round your answer to two decimal places. 44.41 X%
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:At another local coffee shop, wait times for a cup of plain coffee are normally distributed with a mean of 125 seconds and a standard deviation of 22 seconds.
a. What percentage of wait times for a cup of plain coffee are less than 90 seconds? Round the percentage to two decimal places.
0.0
b. What percentage of wait times for a cup of plain coffee are greater than 125 seconds?
50
X %
44.41
c. What percentage of wait times for a cup of plain coffee are between 90 seconds and 125 seconds? Round your answer to two decimal places.
%
89
X %
d. On a particular day, 200 people waited for a plain cup of coffee. How many of them would we expect to have waited between 90 seconds and 125 seconds to get their coffee? Round to the nearest whole
number.
customers

Transcribed Image Text:At the conclusion of training, all factory workers are timed as they complete a task. The completion times for the task are normally distributed.
Suppose a worker's completion time is 0.4 standard deviations above the mean. What is the worker's percentile score? Round your result to one decimal place.
13.6
X %
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