At an air show, a jet has a trajectory following the curve y = 3x². When the jet is at the point (5, 75), it has a speed of 550 km/h. Determine the velocity vector at this point. (Express numbers in exact form. Use symbolic notation and fractions where needed. Give your answer using component form or standard basis vectors.) velocity:

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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### Problem Statement:
At an air show, a jet has a trajectory following the curve \( y = 3x^2 \). When the jet is at the point \( (5, 75) \), it has a speed of 550 km/h. Determine the velocity vector at this point.

(Express numbers in exact form. Use symbolic notation and fractions where needed. Give your answer using component form or standard basis vectors.)

#### Solution:
Determine the velocity:
\[ \text{velocity:} \]

### Explanation:
To solve this problem, we need to find the velocity vector at the specified point and given speed. The velocity vector in a plane can be determined using the parametric form of the position function and differentiating it.

### Finding the Velocity Vector:
1. **Trajectory Equation:**
   \[ y = 3x^2 \]

2. **Coordinates at the Given Point:**
   \[ (5, 75) \]

3. **Speed:**
   \[ \text{Speed} = 550 \text{ km/h} \]

4. **Derivative (velocity components):**
   \[ \text{Let } x(t) \text{ and } y(t) \text{ be the parametric equations. Then, } y = 3x^2 \]
   \[ \text{Differentiate } y \text{ with respect to } x: \]
   \[ \frac{dy}{dx} = 6x \]

5. **Evaluating at \( x = 5 \):**
   \[ \frac{dy}{dx} \bigg|_{x=5} = 6 \cdot 5 = 30 \]

6. **Components of the Velocity (normalized):**
   \[ \text{Let } V_x \text{ and } V_y \text{ be the x and y components of the velocity vector.} \]
   \[ \frac{V_y}{V_x} = 30 \Rightarrow V_y = 30V_x \]

7. **Finding the magnitudes:**
   \[ \sqrt{V_x^2 + V_y^2} = 550 \]
   \[ \sqrt{V_x^2 + (30V_x)^2} = 550 \]
   \[ \sqrt{1 + 900}V_x = 550 \]
   \[ \sqrt
Transcribed Image Text:### Problem Statement: At an air show, a jet has a trajectory following the curve \( y = 3x^2 \). When the jet is at the point \( (5, 75) \), it has a speed of 550 km/h. Determine the velocity vector at this point. (Express numbers in exact form. Use symbolic notation and fractions where needed. Give your answer using component form or standard basis vectors.) #### Solution: Determine the velocity: \[ \text{velocity:} \] ### Explanation: To solve this problem, we need to find the velocity vector at the specified point and given speed. The velocity vector in a plane can be determined using the parametric form of the position function and differentiating it. ### Finding the Velocity Vector: 1. **Trajectory Equation:** \[ y = 3x^2 \] 2. **Coordinates at the Given Point:** \[ (5, 75) \] 3. **Speed:** \[ \text{Speed} = 550 \text{ km/h} \] 4. **Derivative (velocity components):** \[ \text{Let } x(t) \text{ and } y(t) \text{ be the parametric equations. Then, } y = 3x^2 \] \[ \text{Differentiate } y \text{ with respect to } x: \] \[ \frac{dy}{dx} = 6x \] 5. **Evaluating at \( x = 5 \):** \[ \frac{dy}{dx} \bigg|_{x=5} = 6 \cdot 5 = 30 \] 6. **Components of the Velocity (normalized):** \[ \text{Let } V_x \text{ and } V_y \text{ be the x and y components of the velocity vector.} \] \[ \frac{V_y}{V_x} = 30 \Rightarrow V_y = 30V_x \] 7. **Finding the magnitudes:** \[ \sqrt{V_x^2 + V_y^2} = 550 \] \[ \sqrt{V_x^2 + (30V_x)^2} = 550 \] \[ \sqrt{1 + 900}V_x = 550 \] \[ \sqrt
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