At a temperature of 60°F, a 0.03-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v=0.32; a = 12.5 x 10-6/°F] bar with a width of 2.5 in. and a thickness of 0.65 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 9.6x 106/°F] bar with a width of 2.0 in. and a thickness of 0.65 in. The supports at A and C are rigid. Assume h₁=2.5 in., h₂-2.0 in., L₁-26 in., L₂=45 in., and A = 0.03 in. Determine (a) the lowest temperature at which the two bars contact each other. (b) the normal stress in the two bars at a temperature of 265°F. (c) the normal strain in the two bars at 265°F. (d) the change in width of the aluminum bar at a temperature of 265°F. (1) L₁ h₁ B h₂ L2
At a temperature of 60°F, a 0.03-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v=0.32; a = 12.5 x 10-6/°F] bar with a width of 2.5 in. and a thickness of 0.65 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 9.6x 106/°F] bar with a width of 2.0 in. and a thickness of 0.65 in. The supports at A and C are rigid. Assume h₁=2.5 in., h₂-2.0 in., L₁-26 in., L₂=45 in., and A = 0.03 in. Determine (a) the lowest temperature at which the two bars contact each other. (b) the normal stress in the two bars at a temperature of 265°F. (c) the normal strain in the two bars at 265°F. (d) the change in width of the aluminum bar at a temperature of 265°F. (1) L₁ h₁ B h₂ L2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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I have most of the problem done but I need help with parts 9 10 and 11. Thank you!
![At a temperature of 60°F, a 0.03-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000
ksi; v = 0.32; a = 12.5 x 10-6/°F] bar with a width of 2.5 in. and a thickness of 0.65 in. Bar (2) is a stainless steel [E = 28,000 ksi; v =
0.12; a = 9.6 x 10-6/°F] bar with a width of 2.0 in. and a thickness of 0.65 in. The supports at A and Care rigid. Assume h₁=2.5 in.,
h₂=2.0 in., L₁=26 in., L2=45 in., and 4 = 0.03 in. Determine
(a) the lowest temperature at which the two bars contact each other.
(b) the normal stress in the two bars at a temperature of 265°F.
(c) the normal strain in the two bars at 265°F.
(d) the change in width of the aluminum bar at a temperature of 265°F.
(1)
L₁
h₁
B
A
h₂
✓
(2)
L2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc77f544a-ee3e-4902-8958-66e53c68e4a2%2Fcf638f76-942a-4cdd-b7a2-5d3347efa238%2Fvxbhbfq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:At a temperature of 60°F, a 0.03-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000
ksi; v = 0.32; a = 12.5 x 10-6/°F] bar with a width of 2.5 in. and a thickness of 0.65 in. Bar (2) is a stainless steel [E = 28,000 ksi; v =
0.12; a = 9.6 x 10-6/°F] bar with a width of 2.0 in. and a thickness of 0.65 in. The supports at A and Care rigid. Assume h₁=2.5 in.,
h₂=2.0 in., L₁=26 in., L2=45 in., and 4 = 0.03 in. Determine
(a) the lowest temperature at which the two bars contact each other.
(b) the normal stress in the two bars at a temperature of 265°F.
(c) the normal strain in the two bars at 265°F.
(d) the change in width of the aluminum bar at a temperature of 265°F.
(1)
L₁
h₁
B
A
h₂
✓
(2)
L2
Transcribed Image Text:Determine £1,0. the component of the normal strain in Bar (1) due to the internal force F₁. This would be the normal strain in Bar 1
for an internal force F₁ with no effect of the temperature increase included. Also, determine the accompanying lateral strain due
to the Poisson effect al 1.0. Where the lateral strain here is the strain in the direction of the width of 2.5in.
Answers:
£1,0 =
Elat 1,0 =
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Part 10
Answer: Elal 1,7 =
i
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Determine El 1,7. the component of the lateral strain caused by the temperature change.
Part 11
Elat1 =
Swidth =
! με
i
i
με
με
in.
με
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Determine the total lateral strain and the corresponding change in width of the aluminum bar at a temperature of 265°F.
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