At a potential of -1.0 V (versus SCE), carbon tetrachloride in methanol is reduced to chloroform at a Hg cathode: 2CCl4 + 2H+ + 2e + 2Hg (1) ⇒ 2CHCl3 + Hg2 Cl₂ (8) At -1.80 V, the chloroform further reacts to give methane: 2CHCl3 + 8H+ + Be + 6Hg(1)→ 2CH4 + 3Hg2Cl₂ (8) Several 0.850-g samples containing CC14, CHCl3, and inert organic species were dissolved in methanol and electrolyzed at -1.0 V until the current approached zero. A coulometer indicated the charge required to complete the reaction, as given in the second column of the following table. The potential of the cathode was then adjusted to -1.80 V. The additional charge required to complete the reaction at this potential is given in the third column of the table. Calculate the percent CCl4 and CHCI 3 in each mixture.

At a potential of -1.0 V (versus SCE), carbon tetrachloride in methanol is reduced to chloroform at a Hg cathode: 2CCl4 + 2H+ + 2e + 2Hg (1) ⇒ 2CHCl3 + Hg2 Cl₂ (8) At -1.80 V, the chloroform further reacts to give methane: 2CHCl3 + 8H+ + Be + 6Hg(1)→ 2CH4 + 3Hg2Cl₂ (8) Several 0.850-g samples containing CC14, CHCl3, and inert organic species were dissolved in methanol and electrolyzed at -1.0 V until the current approached zero. A coulometer indicated the charge required to complete the reaction, as given in the second column of the following table. The potential of the cathode was then adjusted to -1.80 V. The additional charge required to complete the reaction at this potential is given in the third column of the table. Calculate the percent CCl4 and CHCI 3 in each mixture.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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